Answer:
The answer to your question is 2 molecules, or B(edg 2021).
Explanation:
edg 2021
Answer:
28.75211 kj
Explanation:
Given data:
Mass of iron bar = 841 g
Initial temperature = 84°C
Final temperature = 7°C
Heat released = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
specific heat capacity of iron is 0.444 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 7°C - 84°C
ΔT = -77°C
By putting values,
Q = 841 g × 0.444 j/g.°C × -77°C
Q = 28752.11 j
In Kj:
28752.11 j × 1 kJ / 1000 J
28.75211 kj
Answer:
i. Lead nitrate:
2Pb (NO3)2 Δ= 2PbO+4NO2+O2
ii. Potassium chlorate:
2KClO3 → 2KCl + 3O2↑
iii. clacium carbonate:
CaCO3 + 2HCl -> CaCl2 + CO2 + H2O
iv. cupric carbonate :
CuCO3 → CuO + CO2↑
Hope this helped
All the best!!
