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wlad13 [49]
2 years ago
6

Complete the balanced dissociation equation Cs2CO3

Chemistry
1 answer:
MaRussiya [10]2 years ago
3 0

The balanced dissociation equation for Cs₂CO₃ is:

Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)

A dissociation equation is an equation showing the available ions present in a solution.

To obtain the dissociation equation, the compound must be dissolved in water to produce an aqueous solution.

The dissociation equation for Cs₂CO₃ can be written as follow

Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)

Learn more about dissociation equation: brainly.com/question/1903354

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Mechanical energy is the sum of two types of energy—kinetic energy and potential energy. Which of the following is an example of
DedPeter [7]

Answer:

There is no picture but the one that is in motion in the picture has kinetic energy.

Explanation:

Kinetic energy is the energy of motion.

hope this helped!

5 0
3 years ago
For the reaction 2 HCl + Ca ( OH ) 2 ⟶ CaCl 2 + 2 H 2 O how many grams of calcium hydroxide, Ca(OH)2, are needed to react comple
kari74 [83]

Answer: 65.38g of Ca(OH)2 is needed

Explanation:

From The equation of reaction

2 HCl + Ca ( OH ) 2 ⟶ CaCl 2 + 2 H 2 O

NB: Molar mass of HCl= 1+35.5=36.5

Ca(OH)2= 74

From The stoichiometric equation

2mol of HCl(36.5×2=73) require 1mol of Ca(OH)2 (74g)

Hence 64.5g of HCl will require 64.5×74/73= 65.38g of Ca(OH)2

5 0
3 years ago
If the pressure of a gas sample is quadrupled and the absolute temperature is doubled, by what factor does the volume of the sam
Natasha_Volkova [10]

Answer:

D) 1/2

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given,

P₂ = 4P₁

T₂ = 2T₁

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{P_1}\times {V_1}}{T_1}=\frac {{4\times P_1}\times {V_2}}{2\times T_1}

V_2=\frac{1}{2}\times V_1

<u>The volume change by half of the original.</u>

7 0
3 years ago
Read 2 more answers
PLZZZZZ HELP MEEEEEE
Masja [62]

Answer:

0.0745 mole of hydrogen gas

Explanation:

Given parameters:

Number of H₂SO₄ = 0.0745 moles

Number of moles of Li = 1.5107 moles

Unknown:

Number of moles of H₂ produced = ?

Solution:

To solve this problem, we have to work from the known specie to the unknown one.

The known specie in this expression is the sulfuric acid,  H₂SO₄. We can compare its number of moles with that of the unknown using a balanced chemical equation.

   Balanced chemical equation:

                    2Li   +     H₂SO₄   →   Li₂SO₄   +   H₂

 From the balanced equation;

     

Before proceeding, we need to obtain the limiting reagent. This is the reagent whose given proportion is in short supply. It determines the extent of the reaction.

           2 mole of Li reacted with 1 mole of  H₂SO₄

          1.5107 mole of lithium will react with \frac{1.5107}{2}  = 0.7554mole of H₂SO₄

But we were given 0.0745 moles,

This suggests that the limiting reagent is the sulfuric acid because it is in short supply;

   

   since 1 mole of sulfuric acid produced 1 mole of hydrogen gas;

    0.0745 mole of sulfuric acid will produce 0.0745 mole of hydrogen gas

4 0
3 years ago
in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet,
insens350 [35]

Answer:

The percentage efficiency of the electrical element is approximately 82.186%

Explanation:

The given parameters are;

The thermal energy provided by the stove element, H_{supplied} = 3.34 × 10³ J

The amount thermal energy gained by the kettle, H_{absorbed}  = 5.95 × 10² J

The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}}  \times 100

Therefore, we get;

\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3}  \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%

The percentage efficiency of the electrical element, η% ≈ 82.186%.

4 0
3 years ago
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