Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
So, using the number 3,200,000 deaths per year, you want to divide it until it reaches deaths per minute.
3,200,000 divided by 365 (for days)
8767.123 divided by 24 (for hours)
365.297 divided by 60 (for minutes)
and so you get
6.088 deaths per minute
Hope this helped.
(8/9-3/9)*2/3=5/9*2/3=10/27
Answer:
AB = 34 and AC = 16
BC^2 = 34^2 - 16^2
BC^2 = 1,156 - 256
BC^2 = 900
BC = 30
Step-by-step explanation:
