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2 years ago

Rainforest are generally defined by two factors chose all that apply

Chemistry

2 answers:

katen-ka-za [31]2 years ago

6 0

Answer:

C,D

c. there be 80- 100 inches of rain per year d. no Rian must. be distributed throughout the year

katovenus [111]2 years ago

4 0

Answer:

C and D

C. There must be 80- 100 inches per year

D. No rain must be distributed throughout the year ;)

Explanation:

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In which of the titrations described below will the first (or only) equivalence point be reached upon the addition of 25.0 mL of

Mnenie [13.5K]

Answer:

1, 3, and 4

Step-by-step explanation:

We must calculate the volume of NaOH needed for each titration.

1) HCl

HCl + NaOH ⟶ NaCl + H₂O

n(HCl) = 25.0 mL × (0.100 mmol/1mL) = 2.50 mmol

n(NaOH) = 2.50 mmol HCl × (1 mmol NaOH/1 mmol HCl

= 2.50 mmol NaOH

V(NaOH) = 2.50 mmol × (1 mL/0.100 mmol) = 25.0 mL

2) H₂C₂O₄

H₂C₂O₄ + NaOH ⟶ NaHC₂O₄

n(H₂C₂O₄) = 50.0 mL × (0.100 mmol/1mL) = 5.00 mmol

n(NaOH) = 5.00 mmol H₂C₂O₄ × (1 mmol NaOH/1 mmol H₂C₂O₄)

= 5.00 mmol NaOH

V(NaOH) = 5.00 mmol × (1 mL/0.100 mmol) = 50.0 mL

3) HC₂H₃O₂

HC₂H₃O₂ + NaOH ⟶ NaC₂H₃O₂ + H₂O

n(HC₂H₃O₂) = 25.0 mL × (0.100 mmol/1mL) = 2.50 mmol

n(NaOH) = 2.50 mmol HCl × (1 mmol NaOH/1 mmol HCl)

= 2.50 mmol NaOH

V(NaOH) = 2.50 mmol × (1 mL/0.100 mmol) = 25.0 mL

4) HBr

HBr + NaOH ⟶ NaBr + H₂O

n(HBr) = 25.0 mL × (0.100 mmol/1mL) =2.50 mmol

n(NaOH) = 2.50 mmol HCl × (1 mmol NaOH/1 mmol HCl)

= 2.50 mmol NaOH

V(NaOH) = 2.50 mmol × (1 mL/0.100 mmol) = 25.0 mL

Titrations 1, 3, and 4 reach the first or only equivalence point at 25.0 mL NaOH.

8 0

3 years ago

Read 2 more answers

- Ibrahim and Emmanuel have been investigating the amount of copper sulfate that

nignag [31]

The boys can arrive at the conclusion that as temperature increases, a greater mass of copper sulfate is dissolved in water.

<h3>What is an experiment?</h3>

An experiment is a scientific investigation that seeks to obtain cause and effect relationships. There must be a dependent and an independent variable in every experiment.

The average of the temperature readings is; 20 + 30 + 40 + 50 + 60 + 70 + 80/7 = 50

They used an interval of 10 degrees for the temperature readings. The boys should have kept the heating time the same. The independent variable in this experiment is the temperature. The boys can arrive at the conclusion that as temperature increases, a greater mass of copper sulfate is dissolved in water.

Learn more about dependent and independent variables: brainly.com/question/967776

8 0

2 years ago

(c) ammonium carbonate + lead nitrate ? Step-by-step solution Step 1 of 3 v Step 2 of 3 v Step 3 of 3 ^ c) The ions formed in so

kenny6666 [7]

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium carbonate and lead nitrate is given as:

$(NH_4)_2CO_3(aq.)+Pb(NO_3)_2(aq.)\rightarrow PbCO_3(s)+2NH_4NO_3(aq.)$

Ionic form of the above equation follows:

$2NH_4^+(aq.)+CO_3^{2-}(aq.)+Pb^{2+}(aq.)+2NO_3^-(aq.)\rightarrow PbCO_3(s)+2NH_4^+(aq.)+2NO_3^-(aq.)$

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Pb^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow PbCO_3(s)$