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Misha Larkins [42]
3 years ago
9

What is the salt that is produced when ammonia (nh3) and hydrochloric acid (hcl) react together?

Chemistry
1 answer:
puteri [66]3 years ago
7 0
NH4CI or ammonium chloride
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Help me out please an thank you
ivanzaharov [21]
The second one, I could be mistaken though
3 0
3 years ago
What is the balanced equation for naphthalene and sulphur?​
Marianna [84]

napthalene: C10H8 sulphur: S02

Explanation:

C10H8

7 0
3 years ago
Which of the following is the strongest base? ta) CH,ONa (b) NaNH, (c) CH-CH,Li (0) NaOH (6) CHÚCONa
Mashutka [201]

Hey there:

Correct answer is :

(b) NaNH₂

Sodium azanide NaNH₂ is the conjugate base of ammonia NH₃

Correct answer is :

(b) NaNH₂

I hope this will help !

7 0
3 years ago
Matt has found a book on various marine zones. A picture illustrates a zone that shows diffused penetration of sunlight in water
Ugo [173]

Answer:

the mesopelagic, dysphotic, or twilight zone

Explanation:

Marine zones are the divisions of the ocean. The ocean is divided into two basic parts; the pelagic or open ocean, and the benthic or sea floor.

The pelagic zone is further divided into five broad zones according to how far down sunlight penetrates and they are:

1) the epipelagic, euphotic, or sunlit zone: the top layer of the ocean where enough sunlight penetrates for plants to carry on photosynthesis.

2) the mesopelagic, dysphotic, or twilight zone: a dim zone where some light penetrates, but not enough for plants to grow.

3) the bathypelagic, aphotic, or midnight zone: the deep ocean layer where no light penetrates.

4) the abyssal zone: the pitch-black bottom layer of the ocean; the water here is almost freezing and its pressure is immense.

5) the hadal zone: the waters found in the ocean's deepest trenches.

3 0
3 years ago
The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. what is this distance in cen
e-lub [12.9K]
<span>pm stands for picometer and picometers are units which can be used to measure really tiny distances. One picometer is equal to 10^{-12} meters. We know that one centimeter is equal to 10^{-2} m so there are 10^2 cm per meter. We can change the distance d = 115 pm to units of centimeters. d = (115 pm) x (10^{-12}m / pm) x (10^2 cm / m) d = 115 x 10^{-10} cm = 1.15 x 10^{-8} cm The distance in centimeters is 1.15 x 10^{-8} cm</span>
7 0
3 years ago
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