Answer:
Explanation
Explanation:
Real gases have small attractive and repulsive forces between particles and ideal gases do not. Real gas particles have a volume and ideal gas particles do not. Real gas particles collide in-elastically (loses energy with collisions) and ideal gas particles collide elastically.
Answer:
No matter how many times you cut it, its chemical properties won't change and it'll still be paper.
Explanation:
<u>Answer:</u> The pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.
<u>Explanation:</u>
There are three types of solution: acidic, basic and neutral
To determine the type of solution, we look at the pH values.
- The pH range of acidic solution is 0 to 6.9
- The pH range of basic solution is 7.1 to 14
- The pH of neutral solution is 7.
We are given:
Concentration of HI = 0.100 M
1 mole of HI produces 1 mole of hydrogen ions and 1 mole of iodide ions
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
![[H^+]=0.100M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.100M)
Putting values in above equation, we get:
To calculate the pOH of the solution, we use the equation:
pH + pOH = 14
Hence, the pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.
<span>1.16 moles/liter
The equation for freezing point depression in an ideal solution is
ΔTF = KF * b * i
where
ΔTF = depression in freezing point, defined as TF (pure) ⒠TF (solution). So in this case ΔTF = 2.15
KF = cryoscopic constant of the solvent (given as 1.86 âc/m)
b = molality of solute
i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1.
Solving for b, we get
ΔTF = KF * b * i
ΔTF/KF = b * i
ΔTF/(KF*i) = b
And substuting known values.
ΔTF/(KF*i) = b
2.15âc/(1.86âc/m * 1) = b
2.15/(1.86 1/m) = b
1.155913978 m = b
So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
Answer:
i am pretty sure it is compound
