Ask question

Ask question

All categories

2 years ago

8

Show that the units N/kg can be written using only units of meters (m) and second (s). Is this a unit of mass ,acceleration or f

orce.

1 answer:

nikdorinn [45]2 years ago

3 0

<span>When the difference between two results is larger than the estimates error, the result is</span>

You might be interested in

A box with a mass of 50 kg is raised straight up. What is the force of the box?

8_murik_8 [283]

Answer:

A box with a mass of 50 kg is raised straight up. What is the force of the box? plss help!! two types exist-positive and negative. possible answers: A- electric current B- repel C- lines of force D- charges. Five wavelengths are generated every 0.100 s in a tank of water.

Explanation:

I hope it helped

3 0

1 year ago

If there are two photons with different energies, the one that has a higher energy (a) has the higher frequency (b) has the high

kozerog [31]

Answer:

(a) has the highest frequency

Explanation:

E = hf...where E(is the energy of a photon);h(is the planck's constant) and f is the frequency of the photon

Whereby this formula shows us that energy of a photon is directly proportional to its frequency

So hence if the energy is high then the frequency of the photon is also high

3 0

3 years ago

Using energy considerations, calculate the average force (in N) a 62.0 kg sprinter exerts backward on the track to accelerate fr

slava [35]

Answer:

69.68 N

Explanation:

Work done is equal to change in kinetic energy

W = ΔK = Kf - Ki = $\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}$

W = $F_{total} .d$

where m = mass of the sprinter

vf = final velocity

vi = initial velocity

W = workdone

kf = final kinetic energy

ki = initial kinetic energy

d = distance traveled

Ftotal = total force

vf = 8m/s

vi= 2m/s

d = 25m

m = 60kg

inserting parameters to get:

W = ΔK = Kf - Ki = $\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}$

$F_{total} .d =\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}$

$F_{total} = \frac{\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}}{d}$

$F_{total=} \frac{\frac{1}{2} X 62 X6^{2} -\frac{1}{2} X 62 X2^{2} }{25}$

= 39.7

we know that the force the sprinter exerted F sprinter, the force of the headwind Fwind = 30N

$F_{sprinter} = F_{total} + F_{wind} = 39.7 + 30 = 69.68 N$

7 0

3 years ago

Read 2 more answers

If WEIGHT depends on gravity and the pull of gravity

deff fn [24]

Answer:

The weight will be more on planet B because greater is the gravity more is the weight of a body

4 0

3 years ago

The student wants to collect data to determine the work done by the force due to gravity on the object as it falls. Which of the

ladessa [460]

Answer:

B - spring scale and meterstick

Explanation:

The work done by the force of gravity as the object falls is equal to the potential energy of the object.

We know that the gravitational potential energy(PE) of an object is obtained by;

PE =mgΔh

Where;

m = mass of the object

g = acceleration due to gravity

h= height of the object

The spring scale is needed to measure the mass of the object while the meterstick measures the Δh in meters.

7 0

2 years ago