Answer:
The answer is C.<em>19.8 m/</em><em>s</em><em> </em>because it's their common velocity after the collision of the two cars.
Explanation:
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look at the attachment above ☝️ and if you have any questions you're welcome.
Answer:
B. Make the work you do feel easier
Answer:
Increases is the correct answer.
Explanation:
Just took the quiz.
Answer:
v = (5.2 ± 0.2) 10⁻² m / s
Explanation:
This is an exercise in kinematics of uniform motion. The formula for the average speed is
v = x / t
let's calculate
v = 5.2 / 100
v = 0.052 m / s
v = 5.2 10-2 m / s
we have to find the uncertainty of this quantity we propagate the error using derivatives
Δv = dv /dx Δx + dv /dt Δt
taking everything in the most unfavorable case, I mean all positive
let's make the derivatives
dv / dx = 1 / t
dv / dt = -x / t²
we substitute
Δv = 1 /t Δx + x /t² Δt
let's calculate the error
Δv = 1/100 0.1 + 5.2 / 100² 1
Δv = 1 10⁻³ + 5.2 10⁻⁴
Δv = 1.52 10⁻³ m/s
the error must be given with a significant figure
Dv = 2 10⁻³ m / s
the answer is
v = (5.2 ± 0.2) 10⁻² m / s
Answer:
static friction is developed between 2 surfaces in state of rest so i think answer is c.Even though the wheel is in motion, the patch of the tire in contact with the ground is stationary relative to the ground, so it is static rather than kinetic friction.