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3 years ago

8

Show that the units N/kg can be written using only units of meters (m) and second (s). Is this a unit of mass ,acceleration or f

orce.

1 answer:

nikdorinn [45]3 years ago

3 0

<span>When the difference between two results is larger than the estimates error, the result is</span>

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What's the Coulomb's law?

Ulleksa [173]

<span>
In layman's term: </span>like charges don't attract while opposite charges do<span>electrostatic forces between point A( which is charged) and point B (which is also charged) are proportional to the charge of point A and point B. </span><span>there is also something else about this law that I don't quite remember.</span>

<span>___________________________________________________</span>

<span />Here is the formula:

<span>F = k x Q1 x Q2/d^<span>2</span></span>

<span>What the formula means:</span>

F=force between charges

Q1 and Q2= amount of charge

d=distance between these two charges

k= Coulombs constant (proportionally constant)

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I think that about covers it and hopefully this helped.

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3 years ago

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Leah is making a chart to compare and contrast renewable and non-renewable resources. Which of the following would best complete

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Answer:

d. Can be replaced at the same rate or faster than they are used

Explanation:

I just took the test, and its the right answer. Your welcome ✌

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The case of Allan v. Adam was tried first in a court of first instance. The case was appealed to the intermediate state court of

mezya [45]

There are no more courts of appeal within the state system.

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A basketball player of height 2.40 m is standing 2.60 m in front of a convex spherical mirror of radius of curvature 4.00 m. Det

IrinaVladis [17]

Answer:

The size of the image is 1.04 m.

Explanation:

Given that,

Height of object = 2.40 m

Distance of object = 2.60 m

Radius of curvature =4.00 m

Focal length $f=\dfrac{R}{2}=\dfrac{4.00}{2}=2.00$

We need to calculate the image distance

Using mirror formula

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{2.00}+\dfrac{1}{2.60}$

$\dfrac{1}{v}= \dfrac{23}{26}$

$v=1.13\ cm$

We need to calculate the height of the image

Using formula of magnification

$m=\dfrac{h'}{h}=-\dfrac{v}{u}$

Put the value into the formula

$\dfrac{h'}{2.40}=-\dfrac{1.13}{-2.60}$

$h'=\dfrac{1.13}{2.60}\times2.40$

$h'=1.04\ m$

Hence, The size of the image is 1.04 m

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When connected to a battery, a lightbulb glows brightly. If the battery is reversed and reconnected to the bulb, the bulb will g

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