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1 point energy should be the answer
Answer:
5.1*10^3 J/m^3
Explanation:
Using E = q/A*eo
And
q =75*10^-6 C
A = 0.25
eo = 8.85*10^-12
Energy density = 1/2*eo*(E^2) = 1/2*eo*(q/A*eo)^2 = [q^2] / [2*(A^2)*eo]
= [(75*10^-6)^2] / [2*(0.25)^2*8.85*10^-12]
= 5.1*10^3 J/m^3
Answer:
0.139 rad
Explanation:
We use Snell's law
, where if
is the <em>refractive index</em> of the medium containing the <em>incident ray</em>,
would be the <em>incident angle</em>, and if
is the <em>refractive index</em> of the medium containing the <em>refracted ray</em>,
would be the <em>refraction angle</em>, which we want, so we do:

And finally:

We then insert our values:
