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Semmy [17]
3 years ago
15

At this rate, how long would it take for two continents 3500 kilometers apart to collide?

Physics
1 answer:
meriva3 years ago
5 0

<span>Given:

3,500 kilometers

Find:</span>

 

Years for two continents to collide = ?

 

<span>Solution:

We know that </span>typical motions of one plate relative to another are 1 centimeter per year.

So first, we convert 3,500 km to cm.<span>
</span><span>

</span>

The solution would be like this for this specific problem:

 

1 km = 100,000 cm

3,500 km x 100,000 = 350,000,000 cm

Since we know that 1 cm = 1 year, then that means 350,000,000 cm is equivalent to 350,000,000 years.

 

Therefore, it would take 350 million years for two continents that are 3500 kilometers apart to collide.

<span>
To add, </span>a phenomenon of the plate tectonics of Earth that occurs at convergent boundaries is called the continental collision.

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max2010maxim [7]

Answer:

a. 2.4 ×109  N ⋅ m2/s

b. 48.3 N⋅s /m2  

c. 8.00×104W

Explanation:

See Attached file for explanation

3 0
3 years ago
A system is a group of objects that’s analyzed as one unit. Consider a car moving along a road that has a flat section and a hil
vladimir1956 [14]

Answer:

a) Em= K +U,  b) Em= K

Explanation:

The system in this case is formed by the mobilizes and the hill.

Let's write the expressions correctly and completely.

a) When the car moves in the path, the mechanical energy is the siua of the kinetic energy of the car and the potential energy of the car when going up the hill.

              Em = K + U

be) when the car moves in the flat part all the mechanical energy is formed by its kinetic energy that is calculated with the mass and speed of the car

             Em = K

c) When the car goes up the hill the energy the mechanical energy is conserved, but part of the kinetic energy is transformed into potential energy.

8 0
3 years ago
A can of beans that has mass M is launched by a spring-powered device from level ground. The can is launched at an angle of α0 a
scZoUnD [109]

Hi there!

A.

Since the can was launched from ground level, we know that its trajectory forms a symmetrical, parabolic shape. In other words, the time taken for the can to reach the top is the same as the time it takes to fall down.

Thus, the time to its highest point:
T_h = \frac{T}{2}

Now, we can determine the velocity at which the can was launched at using the following equation:
v_f = v_i + at

In this instance, we are going to look at the VERTICAL component of the velocity, since at the top of the trajectory, the vertical velocity = 0 m/s.

Therefore:
0 = v_y + at\\\\0 = vsin\theta - g\frac{T}{2}

***vsinθ is the vertical component of the velocity.

Solve for 'v':
vsin(\alpha_0) = g\frac{T}{2}\\\\v = \frac{gT}{2sin(\alpha_0)}

Now, recall that:
W = \Delta KE = \frac{1}{2}m(\Delta v)^2

Plug in the expression for velocity:
W = \frac{1}{2}M (\frac{gT}{2sin(\alpha_0)})^2\\\\\boxed{W = \frac{Mg^2T^2}{8sin^2(\alpha _0)}}

B.

We can use the same process as above, where T' = 2T and Th = T.

v = \frac{gT}{sin(\alpha _0)} }\\\\W = \frac{1}{2}M(\frac{gT}{sin(\alpha _0)})^2\\\\\boxed{W = \frac{Mg^2T^2}{2sin^2(\alpha _0)}}

C.

The work done in part B is 4 times greater than the work done in part A.

\boxed{\frac{W_B}{W_A} = \frac{4}{1} = 4.0}

4 0
2 years ago
A person riding on the roof of a freight train throws a ball forward. (a) If we ignore air drag and relative to the ground, is t
mina [271]

Answer:

Explanation:

A ball is thrown in forward direction by a person who is riding on the roof of the moving train.

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-(b) Relative to the freight car, the ball moves at the same speed irrespective of train

4 0
3 years ago
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Genetic material<span>, also </span>known<span> as deoxyribonucleic acid (DNA) and Ribonucleic acid (RNA)</span>
5 0
3 years ago
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