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Ainat [17]
2 years ago
11

A small fan has blades that have a radius of 0.0600 m. When the fan is turned on, the tips of the blades have a tangential accel

eration of 23.7 m/s2 as the fan comes up to speed. What is the angular acceleration α of the blades?
Physics
1 answer:
zhuklara [117]2 years ago
7 0

Answer:

α = 395 rad/s²

Explanation:

Main features of uniformly accelerated circular motion

A body performs a uniformly accelerated circular motion   when its trajectory is a circle and its angular acceleration is constant  (α = cte). In it the velocity vector is tangent at each point to the trajectory and, in addition, its magnitude varies uniformly.

There is tangential acceleration (at) and is constant.

at = α*R     Formula (1)

where

α  is the angular acceleration

R is the radius of the circular path

There is normal or centripetal acceleration that determines the change in direction of the velocity vector.

Data

R = 0.0600 m   :blade radius

at = 23.7 m/s² : tangential acceleration of the blades

Angular acceleration of the blades (α)

We replace data in the formula (1)

at = α*R  

23.7 = α*(0.06)

α = (23.7) / (0.06)

α = 395 rad/s²

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If you walk 3 kilometers in 30 minutes , what is the average speed in kilometers per hour?
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Which kind of force do you exert on an object when you pull it toward you?
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By definition we have to:

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you exert an Applied Force on an object when you pull it towards you

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4 0
3 years ago
Read 2 more answers
Fe₂O3<br> + co<br> →<br> Fe3O4 + CO₂
Goryan [66]

Explanation:

                    Fe₂O₃  + CO  → Fe₃O₄ + CO₂

Balancing the equation above, we can derive simple mathematical equations that are very easy to solve.

             aFe₂O₃  + bCO  → cFe₃O₄ + dCO₂

a,b,c and d are the coefficients needed to balance the equation above;

  Conserving Fe; 2a = 3c

                       O: 3a + b = 4c + 2d

                        C: b = d

 let a = 1;

      c = \frac{2}{3}

      Since b = d

                  3a + d = 4c + 2d

                    3a = 4c + 2d - d

                     3a = 4c + d

           a = 1, c = \frac{2}{3}

                    3 = 4 x \frac{2}{3}  +  d

                   d = \frac{1}{3}

                    b = \frac{1}{3}

multiplying a, b, c and d by 3:

            a = 3    b = 1     c = 2   and d = 1

                  3Fe₂O₃  + CO  → 2Fe₃O₄ + CO₂

Learn more:

Balanced equation brainly.com/question/2612756

#learnwithBrainly

6 0
3 years ago
It has been suggested that rotating cylinders several miles in length and several miles in diameter be placed in space and used
stepladder [879]

Answer:

the required revolution per hour is 28.6849

Explanation:

Given the data in the question;

we know that the expression for the linear acceleration in terms of angular velocity is;

a_{c} = rω²

ω² = a_{c} / r

ω = √( a_{c} / r )

where r is the radius of the cylinder

ω is the angular velocity

given that; the centripetal acceleration equal to the acceleration of gravity a a_{c}  = g = 9.8 m/s²

so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m

Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m

so we substitute

ω = √( 9.8 m/s² / 3909.87 m )

ω = √0.002506477 s²  

ω = 0.0500647 ≈ 0.05 rad/s  

we know that; 1 rad/s = 9.5493 revolution per minute

ω = 0.05 × 9.5493 RPM

ω = 0.478082 RPM  

1 rpm = 60 rph  

so  

ω = 0.478082 × 60

ω = 28.6849  revolutions per hour  

Therefore, the required revolution per hour is 28.6849

7 0
2 years ago
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