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2 years ago

Displacement of the plane?

Physics

1 answer:

dsp732 years ago

5 0

Answer: The Total Displacement between City A and City B is 530 KM

Explanation: The Explanation to the Answer is simple you have to subtract City B To City A

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where the units of x are length and the numbers 2.6 and 5.1 have appropriate units so that U(x) has units of energy. What is the

KiRa [710]

Answer:

x = 1.00486 m

Explanation:

The complete question is:

" The potential energy between two atoms in a particular molecule has the form U(x) =(2.6)/x^8 −(5.1)/x^4 where the units of x are length and the num- bers 2.6 and 5.1 have appropriate units so that U(x) has units of energy. What is the equilibrium separation of the atoms (that is the distance at which the force between the atoms is zero)? "

Solution:

- The correlation between force F and energy U is given as:

F = - dU / dx

F = - d[(2.6)/x^8 −(5.1)/x^4] / dx

F = 20.8 / x^9 - 20.4 / x^5

- The equilibrium separation distance between atoms is given when Force F is zero:

0 = 20.8 / x^9 - 20.4 / x^5

0 = 20.8 - 20.4*x^4

x^4 = 20.8/20.4

x = ( 20.8/20.4 )^0.25

x = 1.00486 m

5 0

3 years ago

Calculate the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m

otez555 [7]

Answer: The period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

Explanation:

Given: Mass = 5 kg

Spring constant = 6 N/m

Formula used to calculate period is as follows.

$T = 2 \pi \sqrt\frac{m}{k}$

where,

T = period

m = mass

k = spring constant

Substitute the values into above formula as follows.

$T = 2 \pi \sqrt\frac{m}{k}\\= 2 \times 3.14 \times \sqrt\frac{5}{6}\\= 5.73 s$

Thus, we can conclude that the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

5 0

3 years ago

HELP!!!!!

devlian [24]

Answer:

Explanation:

6 0

2 years ago

When numbers are very small or very large, it is convenient to either express the value in scientific notation and/or by using a

Oxana [17]

Answer:

5 mg, $5\cdot 10^{-3}g$

Explanation:

First of all, let's rewrite the mass in grams using scientific notation.

we have:

m = 0.005 g

To rewrite it in scientific notation, we must count by how many digits we have to move the dot on the right - in this case three. So in scientific notation is

$m=5\cdot 10^{-3}g$