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netineya [11]
3 years ago
12

It’s mid-afternoon on a lovely, sunny day; it’s 60°F, and the sun is 60° above the horizon. Rays from the sun strike the still s

urface of a shallow pond that is 20 cm deep. The rays of sun cast a shadow of a stick that is completely submerged, and stuck in the sandy bottom of the pond. If 10 cm of the stick is above the sand, what is the length of the shadow?
Physics
1 answer:
rodikova [14]3 years ago
3 0

Answer:

The correct answer is 5.77 cm

Explanation:

Solution

From the question given, let us recall the following,

A sunny day = 60°F and

The sun  above the horizon is = 60°

The surface of a shallow pond is = 20 cm deep

The stick above sand = 10 cm

The next step is to find the length of the shadow

Now,

let CD = stick

BC= Length of shadow

Thus,

CD/BC = Tan 60°

BC = CD/Tan 60°

= 10/√3 = 5.77 cm

Therefore, the length of the shadow is 5.77 cm

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CHECK COMPLETE QUESTION BELOW

you stood on a planet having a mass four times that of earth mass and a radius two times of earth radius , you would weigh?

A) four times more than you do on Earth.

B) two times less than you do on Earth.

C) the same as you do on Earth

D) two times more than you do on Earth

Answer:

OPTION C is correct

The same as you do on Earth

Explanation :

According to law of gravitation :

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F= mg.....(b)

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From law of motion

Put equation b into equation a

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We know from question a planet having a mass four times that of earth mass and a radius two times of earth radius if we substitute we have

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Joe is hiking through the woods when he decides to stop and take in the view. He is particularly interested in three objects: a
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Answer:

A) correct answer is C,   B)   correct answer is b  and C) The correct answer is b

Explanation:

In the exercises of geometric optics, the equation of the constructor tells us the location of the image.

        1 / f = 1 / p + 1 / q

where f is the focal length of the cornea-crystalline system, p and q are the distances to the object and the image.

In this case, the distance to the image on the retina is constant, about 3 cm. Therefore depending on the distance to the object) p = the focal length must change

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The correct answer is b

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