First, let's express the movement of Car A and B in terms of their position over time (relative to car B)
For car A: y=20x-200 Car A moves 20 meters every second x, and starts 200 meters behind car B
For Car B: y= 15x Car B moves 15 meters every second and starts at our basis point
Set the two equations equal to one another to find the time x at which they meet:
20x - 200 = 15x
200 = 5x
x= 40
At time x=40 seconds, the cars meet. How far will Car A have traveled at this time?
Car A moves 20 meters every second:
20 x 40 = 800 meters
Any two-dimensional vector in cartesian (x,y) coordinates can be broken down into individual horizontal and vertical components using trigonometry. If a train goes up a hill with 15 degree incline at a speed of 22 m/s, the horizontal component is 22cos(15)=21.3 m/s and the vertical component is 22sin(15)=5.5 m/s.
The velocity is 4374.45 m/s.
I got the answer by using v=d/t.
20,000meters / 25min= 4,374.45 m/s.
Answer:
v= 4055.08m/s
Explanation:
This is a problem that must be addressed through the laws of classical mechanics that concern Potential Gravitational Energy.
We know for definition that,
We must find the highest point and the lowest point to identify the change in energy, so
Point a)
The problem tells us that an object is dropped at a distance of h = 1.15134R over the earth.
That is to say that the energy of that object is equal to,
Point B )
We now use the average radius distance from the earth.
Then,
By the law of conservation of energy we know that,
clearing v,
Therefore the speed of the object when it strikes the Earth’s surface is 4055.08m/s
Answer:
Decrease in speed
Explanation:
Increasing an object's velocity can decrease kinetic energy. *The velocity of an object has no effect on kinetic energy. *Increasing an object's velocity can increase kinetic energy. Increasing an object's velocity can increase kinetic energy.
