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adoni [48]
3 years ago
6

In nuclear fission, a nucleus splits roughly in half. (a) What is the electric potential 5.24 10-14 m from a fragment that has 3

6 protons in it? V (b) What is the electric potential energy in MeV of a similarly charged fragment at this distance?
Physics
1 answer:
yKpoI14uk [10]3 years ago
4 0

Answer:

Part A:

Electric potential =V=9.8821*10^5 V

Part B:

Electric Potential Energy=U=35.57556 MeV

Explanation:

Part A:

Charge on the fragment that has 36 Protons in it:

Charge on single roton=1.6*10^{-19} C

Charge on 36 protons=36*1.6*10^{-19} C

Charge on 36 protons=5.76*10^{-18}\ C

Distance=r=5.24*10^{-14}\ m

Formula For electric potential V:

V=\frac{kQ}{r}

Where

k is coulomb constant=8.99*10^9\ N.m^2/C^2

r is the distance

Q is the charge on 6 protons

V=\frac{5.76*10^{-18}*8.99*10^9}{5.24*10^{-14}}\\V=988213.7405 V\\V=9.8821*10^5 V

Electric potential =V=9.8821*10^5 V

Part B:

Electric Potential Energy=U

U=q*V

V is the electric potential

q is the number of protons

U=36*9.8821*10^5 \\U=35575560 eV\\U=35.57556 MeV

Electric Potential Energy=U=35.57556 MeV

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800 N

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By Newton's third law which states that for every action, there is an equal and opposite reaction.

So, as the earth attracts the person towards its center, the person attracts the earth towards itself with the same magnitude of force but in the opposite direction.

Since the person is attracted towards the center of the earth by an 800 N gravitational force, the  the earth is attracted toward the person with an 800 N reaction force.

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Many caterpillars construct cocoons from silk, one of the strongest naturally occurring materials known. Each thread is typicall
joja [24]

Answer:

a) N = 145,833,674.52174 = 1.458 × 10⁸ strands

b) diameter of single rope with the same effect = 2.415 cm

Explanation:

Hooke's law explains that stress is directly proportional to strain.

Stress ∝ Strain.

Stress = E × Strain

E = constant of proportionality = Young's Modulus = 4.0 ✕ 10⁹ N/m².

Stress = (Load/Total Cross sectional Area)

Load = a pair of 85 kg mountain climbers = 85 × 2 × 9.8 = 1666 N

Total Cross sectional Area = (Number of strands) × (Area of one strand) = A

Strain = (ΔL/L)

ΔL = 1.00 cm = 0.01 m

L = 11 m

Strain = (0.01/11) = 0.0009091

Stress = (Young's Modulus) × (Strain) = (4.0 ✕ 10⁹) × (0.0009091) = 3,636,363.64 N/m²

(Load/ total Area) = 3,636,363.64

Total area = (Load/3,636,363.64) = (1666/3,636,363.64) = 0.00045815 m²

Recall,

Total Cross sectional Area = (Number of strands) × (Area of one strand)

Area of one strand = (πd²/4)

diameter of one strand = 2 μm = (2×10⁻⁶) m

Area of one strand = (πd²/4)

= π × (2×10⁻⁶)² ÷ 4 = (3.142 × 10⁻¹²) m²

Total Cross sectional Area = (Number of strands) × (Area of one strand)

0.00045815 = N × (3.142 × 10⁻¹²)

N = 145,833,674.52174 = 1.458 × 10⁸ strands

b) If it was a single rope, the cross sectional Area would just be equal to the total cross sectional Area obtained in (a)

A = 0.00045815 m²

A = (πD²/4)

where D = diameter of the single rope

0.00045815 = (πD²/4)

D² = (4×0.00045815) ÷ π = 0.0005833347

D = 0.02415 m = 2.415 cm

Hope this Helps!!!

6 0
3 years ago
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