Answer:
Part A:
Electric potential =
Part B:
Electric Potential Energy=U=
Explanation:
Part A:
Charge on the fragment that has 36 Protons in it:
Charge on single roton=
Charge on 36 protons=
Charge on 36 protons=
Distance=r=
Formula For electric potential V:
Where
k is coulomb constant=
r is the distance
Q is the charge on 6 protons
Electric potential =
Part B:
Electric Potential Energy=U
U=q*V
V is the electric potential
q is the number of protons
Electric Potential Energy=U=
Complete Question
A radio technician measures the frequency of an AM radio transmitter. The frequency is 14603 kHz . What is the frequency in megahertz? Write your answer as a decimal.
Answer:
The value is
Explanation:
From the question we are told that
The frequency is
Generally
=>
=>
Answer:
Given:
Mass (m) = 3.0 kg
Uniform speed (v) = 20 m/s
Length of string (r) = 40 cm = 0.4 m
To Find:
Tension in the string (T)
Explanation:
Tension (T) is the string will be equal to centripetal force ().
Substituting value of m, v & r in the equation:
Tension in the string (T) = 3 kN
Answer:
P = 33.6 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = forces [N]
m = mass = 14 [kg]
a = acceleration = 6 [m/s²]
In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.
where:
W = work [J]
F = force = 84 [N]
d = displaciment = 40 [m]
Finally, the power can be calculated by the relationship between the work performed in a given time interval.
where:
P = power [W]
W = work = 3360 [J]
t = time = 100 [s]
Now replacing:
The power is given in watts