Answer:
option a is correct
Explanation:
<h2>I hope it's help you ❣️❣️</h2>
Answer:
Centripetal acceleration
Explanation:
- The centripetal acceleration is the motion inwards towards the center of a circular path.
- <em><u>Centripetal acceleration is given by; the square of the velocity, divided by the radius of the circular path.
</u></em>
ac = v²/r
Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the radius, m
The given question is incomplete. The complete question is as follows.
In a nuclear physics experiment, a proton (mass 
kg, charge +e = 
C) is fired directly at a target nucleus of unknown charge. (You can treat both objects as point charges, and assume that the nucleus remains at rest.) When it is far from its target, the proton has speed 
m/s. The proton comes momentarily to rest at a distance 
m from the center of the target nucleus, then flies back in the direction from which it came. What is the electric potential energy of the proton and nucleus when they are 
m apart?
Explanation:
The given data is as follows.
Mass of proton = 
kg
Charge of proton = 
Speed of proton = 
Distance traveled = 
We will calculate the electric potential energy of the proton and the nucleus by conservation of energy as follows.
= 
where, 
U = 
Putting the given values into the above formula as follows.
U =
= 
= 
Therefore, we can conclude that the electric potential energy of the proton and nucleus is .
Explanation:
7.7 m/s
1st determine you subject slade to you have a mass of 15 kg being subjected to a force of 180N
so.
180N/15kg=180(kg m)/s^2/15kg=12 ms^2
now determine how long u pushed it
d=0.5 A T^2
sutable the known values getting
2.5 m = 0.5 12 ms^2 T^2
2.5m= 0.6 ms^2 T^2
0.41667 s^2=T^2
0.645497224s=T
the velocity multiply the time by the acceleration giving
0.645497224 s 12 ms^2 =7.745966692 ms.
after rounding the 2 significant u get 7.7 ms
