3 years ago

Which one of the risk factors that influence you learn how may be most difficult to control as a young teen

Physics

1 answer:

nalin [4]3 years ago

8 0

I hope my answer helped u under stand better

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Calculate the acceleration using the formula acceleration = (final velocity - initial velocity) / time.

PtichkaEL [24]

Answer:

10 km/hr/s

Explanation:

The acceleration of an object is given by

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time

For the car in this problem:

u = 0

$v=60 km/h$

t = 6 s

Substituting in the equation,

$a=\frac{60 km/h-0}{6s}=10 km/h/s$

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Monica divorced Robert last year because she was not satisfied with the amount of money he earned and was distressed by their fi

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The answer was that the last time we A

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Quanto tempo deve ficar ligado um ferro eletrico de 1000 w para que tenha o mesmo consumo de energia que um chuveiro de 4400 w q

Cerrena [4.2K]

Answer:

Thus, the time for the first lamp is 44 minutes.

Explanation:

Power of first lamp, P' = 1000 W

Power of second lamp, P'' = 4400 W

time for second lamp, t'' = 10 minutes

Let the time for first lamp is t'.

As the energy is same, so,

P' x t' = P'' x t''

1000 x t' = 4400 x 10

t' = 44 minutes

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3 years ago

2.10-kg box is moving to the right with speed 8.50 m>s on a horizontal, frictionless surface. At t = 0 a horizontal force is

larisa86 [58]

Explanation:

Below is an attachment containing the solution.

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A laser beam is incident on two slits with a separation of 0.230 mm, and a screen is placed 4.75 m from the slits. If the bright

Mariulka [41]

Answer:

$7.55\times 10^{-7} m$

Explanation:

We are given that

d=0.23 mm= $0.23\times 10^{-3} m$

$1mm=10^{-3} m$

Screen is placed from the slits at distance ,L=4.75 m

The bright interference fringes on the screen are separated by 1.56 cm.

$\Delta y=1.56 cm=1.56\times 10^{-2} m$

1 m=100 cm

We have to find the wavelength of laser light.

We know that

$\Delta y=\frac{\lambda L}{d}$

Substitute the values

$1.56\times 10^{-2}=\frac{\lambda\times 4.75}{0.23\times 10^{-3}}$

$\lambda=\frac{1.56\times 10^{-2}\times 0.23\times 10^{-3}}{4.75}$

$\lambda=7.55\times 10^{-7} m$

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3 years ago