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pashok25 [27]
3 years ago
5

The speed of light in a vacuum is 2.998 x 108 m/s. Calculate its speed in miles per hour.

Physics
1 answer:
baherus [9]3 years ago
7 0

Answer:

Answer:

I don't know

Explanation:

I don't know

Explanation:

Answer:

I don't know

Explanation:

I don't know

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Tarzan is testing the strength of a particular vine, which is 7 m long. As he is hanging on the vine, what is the magnitude of t
pentagon [3]

Answer:

the tension generated on the vine is equal to 784.8 N

Explanation:

As Tarzan is testing the strength of vine

to test the vine Tarzan hangs on it.

given,

mass of Tarzan  = 80 kg

acceleration due to gravity = 9.81 m/s²

tension on the wire will be            

     T = m × g                    

     T = 80 kg × 9.81 m/s²                

     T = 784.8 kg.m/s²                

     T = 784.8 N                    

hence, the tension generated on the vine is equal to 784.8 N

3 0
3 years ago
Weather stays the same all the time true or false
Vlad1618 [11]
This question is false because it is not hot or cold every single day
5 0
3 years ago
Read 2 more answers
- Atoms of different elements:
TiliK225 [7]
(C) have the same heat capacity
3 0
3 years ago
Ben wants to model how the motion of particles changes with temperature. He considers water in an iron pot. Ben draws a model to
Lilit [14]

Answer:

The particles should move faster and have more space between them.

Explanation:

As the molecules heat, they should start to vibrate with the energy. When they vibrate, the space between them increases.

7 0
4 years ago
Three charges 1.5*10-6, 3*10-6, -3*10-6 are placed at three vertices of an equilateral triangle of side 30cm. Find the net force
gulaghasi [49]

Answer:

F = 0N

Explanation:

The force between two charges is given by

F=k\frac{q_1q_2}{r^2}

where r is the distance between the charges and K is the Coulomb's constant

(k=8-89*10^9Nm^2/C^2)

The force in the first charge is only the sum of the forces due to the other charges. Hence we have

F_T=F_1+F_2=k\frac{q_2q_1}{r^2}+k\frac{q_3q_1}{r^2}

F_T=(8.89*10^9\frac{Nm^2}{C^2})\frac{(3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}+(8.89*10^9\frac{Nm^2}{C^2})\frac{(-3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}\\\\F_T=0.445N-0.445N=0N

Ft=0N

Hope this helps!!

5 0
3 years ago
Read 2 more answers
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