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4 years ago

A child’s toy rake is held so that its output arm is 0.75 meters. If the mechanical advantage is 0.33, what is

1 answer:

4 0

Input= ?
Output= 0.75
MA= 0.33

So I just kept on Dividing numbers until I was close to "0.33" & I cam up with the answer of .......... 0.25.

So when you divide 0.25 by 0.75 you get the MA of 0.33

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Two concentric current loops lie in the same plane. The outer loop has twice the diameter of the inner loop. The inner loop carr

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Answer: The outer loop should carry a current of 2.0 A.

The current should flow in the counter-clockwise direction

Explanation: Please see the attachments below

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3 years ago

What kind of front occurs when a cold air mass replaces a warm air mass?

Andreyy89

Answer:

Explained below:

Explanation:

When a cold air mass meets a warm air mass, a front is formed and if the cold air is replacing the warm air, it is known as a cold front. Cold fronts frequently cause thunderstorms or rain showers because they pressure the air in a steep upward direction at the front's edge. They are also responsible to bring the changes in atmospheric pressure and wind direction.

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4 years ago

What are three sources of background radiation

Maksim231197 [3]

Answer:

Cosmic Radiation.

Terrestrial Radiation.

Internal Radiation.

Explanation:

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2 years ago

Read 2 more answers

Place the single weight with a known mass on the spring and release it. Eventually, the weight will come to rest at an equilibri

aliya0001 [1]

Answer:

X=m*g/K

Explanation:

Since the elastic force of the spring is balancing the force of gravity:

Fe = m*g

Now, on the spring by Hook's law, the magnitude of the elastic force will be:

Fe = K*X where K is the elastic constant of the spring and X is the distance the spring is strectches measured from its original lenght to its current length.

Replacing this value:

K*X = m*g Solving for X:

X = m*g/K This value is directly proportional to the object's weight and inversely proportional to the spring's constant.

3 0

4 years ago

A 0.5 kg basketball moving 5 m/s to the right collides with a 0.05 kg tennis

Natali5045456 [20]

Answer:

A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

$M_{before} = M_{after}$

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

$(m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})$

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 = velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

Now replacing and solving:

(0.5*5) - (0.05*30) = (0.5*v3) + (0.05*34)

1 - (0.05*34) = 0.5*v3

- 0.7 = 0.5*v

v = - 1.4 [m/s]

The negative sign means that the movement is towards left

3 0

3 years ago