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Pepsi [2]
3 years ago
8

Two small spheres spaced 20.0 cm apart have equal charge. how many excess electrons must be present on each sphere if the magnit

ude of the force of repulsion between them is 4.57 * 10-21 n?
Physics
1 answer:
uysha [10]3 years ago
8 0
<span>890 Coulomb's law is F = k * q1 * q2 / r^2 where F = force k = Coulomb's constant 8.99x10^9 N m^2/C^2 q1,q2 = signed charges r = distance between charges Since the charges are the same, let's simplify the equation, solve for q, then substitute the known values and calculate. F = k * q1 * q2 / r^2 F = k * q^2 / r^2 F*r^2 = k * q^2 F*r^2/k = q^2 sqrt(F*r^2/k) = q sqrt(4.57x10^-21 N * (0.2m)^2 / (8.99x10^9 N m^2/C^2)) = q sqrt((4.57x10^-21 N * 0.04m^2) / (8.99x10^9 N m^2/C^2)) = q sqrt((1.828x10^-22 N*m^2) / (8.99x10^9 N m^2/C^2)) = q sqrt(2.03337x10^-32 C^2) = q 1.42596x10^-16 C = q So each sphere has to have an excess of 1.42596x10^-16 Coulombs of electrons. A coulomb is 6.24150934x10^18 electrons, so let's do the multiplication: 1.42596x10^-16 * 6.24150934x10^18 = 8.9001426584664x10^2 = 890 So each sphere has an extra 890 electrons.</span>
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A sailor strikes the side of his ship just below the surface of the sea. he hears the echo of the wave reflected from the ocean
Luden [163]

Answer: 3750 m


Explanation:


1) You can find in the literature or internet that the speed of sound in the ocean is about 1500 m/s.


2) Then, you can find the distance travel by the sound wave in 5.0s with the equation distance = speed × time


⇒ distance = 1500m/s × 5.0 s = 7500 m


3) That sound went down until the ocean floor below and cameback all the way until the sailor heard it.


Then, the deep of the ocean fllor is half that distance:


deep = 7500m / 2 = 3750m

3 0
3 years ago
1) Describe the motions of the moon relative to the Earth and the sun. Explain how this causes us to see phases of the moon, and
AleksAgata [21]

Answer:

Explanation:

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At new moon, the face of the moon reflect no light. But reflects 100% at full moon. While both 1st and 3rd quarters show partial reflections.

5 0
3 years ago
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The generator will work only if the magnetic field associated with the turns of coil change.

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5 0
3 years ago
Two charged spheres are 8.45 cm apart. They are moved, and the force on each of them is found to have been tripled. How far apar
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Force between two charges is given by

F = \frac{kq_1q_2}{r^2}

here force is inversely depends on the square of the distance

so here if distance is decreased the force will increase'

now if force is tripled

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initially distance between charges was 8.45 cm

3 = \frac{8.45^2}{r'^2}

r' = \frac{8.45}{\sqrt3}

r' = 4.88 cm

so the distance between charges is 4.88 cm now

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3 years ago
De acuerdo a la trayectoria que describe el movimiento de la
dusya [7]

Answer:

With a circle.

Explanation:

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