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Pepsi [2]
3 years ago
8

Two small spheres spaced 20.0 cm apart have equal charge. how many excess electrons must be present on each sphere if the magnit

ude of the force of repulsion between them is 4.57 * 10-21 n?
Physics
1 answer:
uysha [10]3 years ago
8 0
<span>890 Coulomb's law is F = k * q1 * q2 / r^2 where F = force k = Coulomb's constant 8.99x10^9 N m^2/C^2 q1,q2 = signed charges r = distance between charges Since the charges are the same, let's simplify the equation, solve for q, then substitute the known values and calculate. F = k * q1 * q2 / r^2 F = k * q^2 / r^2 F*r^2 = k * q^2 F*r^2/k = q^2 sqrt(F*r^2/k) = q sqrt(4.57x10^-21 N * (0.2m)^2 / (8.99x10^9 N m^2/C^2)) = q sqrt((4.57x10^-21 N * 0.04m^2) / (8.99x10^9 N m^2/C^2)) = q sqrt((1.828x10^-22 N*m^2) / (8.99x10^9 N m^2/C^2)) = q sqrt(2.03337x10^-32 C^2) = q 1.42596x10^-16 C = q So each sphere has to have an excess of 1.42596x10^-16 Coulombs of electrons. A coulomb is 6.24150934x10^18 electrons, so let's do the multiplication: 1.42596x10^-16 * 6.24150934x10^18 = 8.9001426584664x10^2 = 890 So each sphere has an extra 890 electrons.</span>
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2 years ago
The speed of light is about 300,000 km/s (3×105km/s). If Jupiter is 0.72 light hours from the Sun, how far is this?
Daniel [21]

Answer:

7.77 x 10⁸ Km

Explanation:

given,

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                        = 3 x 10⁸ m/s

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now,

0.72 light hour = 0.72 x 1.079 x 10⁹ Km

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7 0
3 years ago
Read 2 more answers
How do you find distance on a velocity time graph?
vekshin1

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How does reflection differ from refraction and diffraction?
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No initial velocity so equation becomes;

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Car B d=4*Car A

So car B has travelled 4 times as far as car A
5 0
3 years ago
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