Why do alpha particles and nuclei repel each other rather than attract eachother

If he leaves the ramp with a speed of 31.0 m/s and has a speed of 29.5 m/s at the top of his trajectory, determine his maximum h

raketka [301]

Answer:

The maximum height reached is 4.63 m.

Explanation:

Given:

Initial speed of the man (u) = 31.0 m/s

Speed at the top of trajectory ( $u_x$ ) = 29.5 m/s

Acceleration due to gravity (g) = 9.8 m/s²

When the man reaches the top of the trajectory, the vertical component of velocity becomes zero and hence only horizontal component of velocity acts on him.

Also, since there is no net force acting in the horizontal direction, the acceleration is zero in the horizontal direction from Newton's second law. Thus, the horizontal component of velocity always remains the same.

So, speed at the top of trajectory is nothing but the horizontal component of initial velocity.

Now, initial velocity can be rewritten in terms of its components as:

$u^2=u_x^2+u_y^2$

Where, $u_x\ and\ u_y$ are the initial horizontal and vertical velocities of the man.

Now, plug in the given values and simplify. This gives,

$(31.0)^2=(29.5)^2+u_y^2\\\\961=870.25+u_y^2\\\\u_y^2=961-870.25\\\\u_y^2=90.75\ m^2/s^2--------1$

Now, we know that, for a projectile motion, the maximum height is given as:

$H=\frac{u_y^2}{2g}$

Plug in the value from equation (1) and 9.8 for 'g' to solve for 'H'. This gives,

$H=\frac{90.75}{2\times 9.8}\\\\H=4.63\ m$

Therefore, the maximum height reached is 4.63 m.

3 0

4 years ago

A clindrical rod of uniform density is located with its center at the origin, and its axis along the axis. It rotates about its

zhenek [66]

Answer:

6093.2328 J

Explanation:

For cylindrical rod moment of inertia will be

$I_X=I_Y=\frac{1}{12}m(3r^2+h^2)$

$I_X=I_Y=\frac{1}{12}\times 4(3\times 0.06^2+0.6^2)=0.1236$ $kg -m^2$

we have given time =0.02 sec

Angular speed = $\frac{2\pi }{T}=\frac{2\times 3.14}{0.02}=314\ rad/sec$

Rotational KE = $\frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.1236\times 314^2=6093.2328\ J$

5 0

3 years ago

vehicles equipped with disc brakes incorporate a mechanically operated drum-style parking brake in the center of the rear disc b

umka21 [38]

Vehicles equipped with disc brakes incorporate a mechanically operated drum-style parking brake in the center of the rear disc brake rotors, commonly called a top hat parking brake.

<h3>What is top hat parking brake?</h3>

The top hat drum style of parking brake system is called the top hat rotors because of how big the middle part is compared to regular rotors.

In this type of parking brake system, the vehicle is equipped with disc brakes which incorporate a mechanically operated drum-style parking brake in the center of the rear disc brake rotors.

Thus, vehicles equipped with disc brakes incorporate a mechanically operated drum-style parking brake in the center of the rear disc brake rotors, commonly called a top hat parking brake.

Learn more about top hat parking brake here: brainly.com/question/21854030

4 0

2 years ago

What is the electric force on a proton 2.5 fm from the surface of the nucleus? hint: treat the spherical nucleus as a point char

Whitepunk [10]

In this case, you need the formula below where:

F = force
k = coulombs constant 8.99 x10^{9} N.m^{2} . C^{-2}
q1 = electric charge 1
q2 = electric charge 2
r = the distance between the charges

$F = k((q1.q2)/r^{2})$

pls note: make sure your units are correct (in meters etc, not fm (<em>femto-meters</em>)).

Curiously, this question doesn't tell you what atom you are next to the nucleus of. Different numbers of protons in the nucleus of the atom will make for vastly different forces in your answer...

6 0

3 years ago

If two opposing forces are equal, then the net force is 0 N.<br><br> true or false?

Fofino [41]

Answer:

false

Explanation:

6 0

3 years ago