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Alja [10]
3 years ago
6

Calculate the final speed of a 110-kg rugby player who is initially running at 8.00 m/s but collides head-on with a padded goalp

ost and experiences a backward force of 1.76×104 n for 5.50×10–2 s .
Physics
1 answer:
Contact [7]3 years ago
6 0
<span>The answer is -0.8 m/s. We know acceleration is the average of final minus initial velocity over time (a = (vf-v0)/t). We also know that Force is equal to Mass times Acceleration (F = ma). Using our force equation, we know that the acceleration we get is negative 8.8 (-8.8). The force is acting in the opposite direction of the rugby player, hence the negative sign. From there, plug in that number for a in the velocity equation, and solve for vf, as v0 and t are known. We get 0.8 m/s in the opposite direction that the player was running.</span>
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A force of 25 newtons moves a box a distance of 4 meters in 5 seconds.
Simora [160]

By definition, we have that the work done is given by:

W = F * d

Where,

F: force in the direction of displacement

d: displaced distance

Substituting values we have:

W = (25) * (4)\\W = 100 Nm

Then, the power is given by:

P = \frac{W}{t}

Where,

t: time

Substituting values we have:

P = \frac{100}{5}

P = 20\frac{Nm}{s}

Answer:

The work done on the box is 100 Nm, and the power is 20 Nm/s.

5 0
3 years ago
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How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?
Akimi4 [234]

Answer:19.5 m

Explanation:

Given

coefficient of kinetic Friction \mu _k=0.10

Initial speed u=3.9\ m/s

Friction is present so it tries to stop to the object and stops it completely after moving certain distance let say s

maximum deceleration provided by friction is

a_{max}=\mu _k\cdot g

a_{max}=0.1\times 3.9=0.39\ m/s^2

using equation of motion

v^2-u^2=2 as

where v=final\ velocity

u=initial velocity

a=acceleration

s=displacement

(0)-(3.9)^2=2\times (-0.39)\times s

s=19.5\ m

6 0
3 years ago
Which statement best describes inertia?
alukav5142 [94]
B if earth had no atmosphere a baseball would fall towards earth at a faster rate
4 0
2 years ago
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Describe the laws of liquid pressure and Explain the term fluid. (Please give the correct answer, it's really urgent)​
Alla [95]

Answer:

The laws of liquid pressure are  

(i) Pressure inside the liquid increases with the depth from the free surface of the liquid.

(ii) Pressure is same at all points on a horizontal plane, in case of stationary liquid.

(iii) Pressure is same in all directions about a point inside the liquid.

(iv) Pressure at same depth is different in different liquids. It increases with the increase in the density of the liquid.

(v) A liquid will always seek its own level.

A Fluid is any liquid or gas or generally any material that cannot sustain a tangential, or shearing, force when at rest.  

Explanation:

3 0
2 years ago
If you stood on a planet having a mass four times that of earth mass and a radius two times of earth radius , you would weigh?
trasher [3.6K]

Answer: Weight will remain same as on the Earth

Explanation :

From Universal law of gravitation :

F=G\dfrac{M_em}{R^2}......(1)

M_e is the mass of earth

m is the mass of the person

R is the radius of the earth

We know that F= mg.....(2)

So, from equation (1) and (2)

mg=\dfrac{GM_em}{R^2}

g=\dfrac{GM_e}{R^2}.....(3)

It is given that, If we stood on a planet having a mass four times that of earth mass and a radius two times of earth radius then from equation (3)

g=\dfrac{G\times 4M_e}{4R^2}

The value of g is will not change. So, our weight would not change. It would remain the same as on the Earth.

8 0
3 years ago
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