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PSYCHO15rus [73]
3 years ago
13

Please guys help please

Mathematics
1 answer:
almond37 [142]3 years ago
4 0
Wild guess a I’m only guessing
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Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
What is the distance between points A and B? (Use only digits 0-9 to write the distance.)
qwelly [4]

Answer:

8

Step-by-step explanation:

A is on the negative side so you count the distanse as -6 -5 -4 so on and then you get to 0 and then its 12345678

3 0
2 years ago
I just need the 4th not the 3rd please help I will give you BRAINLIEST!!!!​
mina [271]

Answer:

See attached

Step-by-step explanation:

The answer is in the picture below

3 0
3 years ago
This is a graph of y=x2-5
PolarNik [594]

Answer:

Yes, it is a graph

Step-by-step explanation:

6 0
3 years ago
Prove that if a is equivalent to 5 mod (8) and b is equivalent to 3 mod (8), then 8 divides ab+1
olga nikolaevna [1]

Answer:

Explanation contains the proof.

Step-by-step explanation:

a \equiv 5 (mod 8) \text{ means there is integer } k \text{ such that } a-5=8k.

b \eqiv 3 (mod 8) \text{ means there is integer } m \text{ such that } b-3=8m.

We want to show that 8 \text{ divides } ab+1.  So we are asked to show that there exist integer n \text{ such that } 8n=ab+1 \text{ or 8n-1=ab

So what is ab?

a-5=8k \text{ gives us } a=8k+5.

b-5=8m \text{ gives us } b=8m+5.

So back to ab....

ab

=(8k+5)(8m+5)

=64km+40k+40m+25  (I use foil to get this)

Factoring out 8 gives us:

=8(8km+5k+5m)+25

Now I could have factored some 8's out of 25.  There are actually three 8's in 25 with a remainder of 1.

=8(8km+5k+5m+3)+1

We have shown that there is integer n \text{ such that } ab=8n-1.

The integer I found that is n is 8km+5k+5m+3.

Therefore 8|(ab+1).

//

5 0
3 years ago
Read 2 more answers
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