<span>2AlPO4 ( aq) + 3MgCl2 (aq) -> Mg3(PO4)2 (s) + 2AlCl3 (aq) </span>
<span>Right answer is D
</span>
Chlorine is more reactive than argon, because argon is not reactive at all. Chlorine only has to gain 1 valence electron
Answer:
The easiest way to identify a double displacement reaction is to check to see whether or not the cations exchanged anions with each other.
Explanation:
if the states of matter are cited, is to look for aqueous reactants and the formation of one solid product (since the reaction typically generates a precipitate).
Sodium chloride's solubility only changed about 5 g/100 mL water, whereas potassium nitrate's solubility changed about 230 g/100 mL water
The calculated enthalpy values are as follows:
- Total enthalpy of reactants = -103.85 KJ/mol
- Total enthalpy of products = -2057.68 KJ/mol
- Enthalpy of reaction = -1953.83 kJ/mol
<h3>What is the enthalpy of the reaction?</h3>
The enthalpy of the reaction is determined as follows:
- Enthalpy of reaction = Total enthalpy of products -Total enthalpy of reactants
- Total enthalpy of reactants = (ΔHf of Reactant 1 x Coefficient) + (ΔHf of Reactant 2 x Coefficient)
- Total enthalpy of products= (ΔHf of Product 1 x Coefficient) + (ΔHf of Product 2 x Coefficient)
Equation of reaction equation: C₃H₈ (g) + 5 O(g) → 4 H₂O(g) + 3CO₂(g)
Total enthalpy of reactants = (-103.85 * 1) + (0 * 5)
Total enthalpy of reactants = -103.85 + 0
Total enthalpy of reactants = -103.85 KJ/mol
Total enthalpy of products = (-393.51 * 4) +(-241.82 * 3)
Total enthalpy of products = (-1574.04) + (-483.64)
Total enthalpy of products = -2057.68 KJ/mol
Enthalpy of reaction = -2057.68 KJ/mol -(-103.85 KJ/mol)
Enthalpy of reaction = -1953.83 kJ/mol
In conclusion, the enthalpy of the reaction is determined from the difference between the total enthalpy of products and reactants.
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