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4vir4ik [10]
2 years ago
9

Explain how light is produced in neon signs.

Chemistry
2 answers:
djyliett [7]2 years ago
8 0

Answer:

The energy that makes light is 'produced' when you pass a high-voltage alternating current through a low-pressure gas sealed in a glass tube.

Explanation:

Harrizon [31]2 years ago
7 0
The other person is right I’m pretty sure
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Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
Sauron [17]

Answer:

The concentration of COF₂ at equilibrium is 0.296 M.

Explanation:

To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:

   2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I      2.00              0              0

C      -2x              +x            +x

E   2.00 - 2x         x              x

Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".

Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852

The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M

6 0
3 years ago
The low-grade iron ore taconite, which contains Fe3O4, is concentrated and made into pellets for processing. If one ton of tacon
xenn [34]

<u>Answer:</u> The percent composition of Fe_3O_4 in taconite is 37.6 %.

<u>Explanation:</u>

We are given:

Mass of taconite pellets = 1 ton = 907185 g      (Conversion factor: 1 ton = 907185 g)

Mass of iron produced = 545 lb = 247212 g    (Conversion factor:  1 lb = 453.6 g )

We know that:

Molar mass of iron = 55.85 g/mol

Molar mass of Fe_3O_4 = 231.53 g/mol

1 mole of Fe_3O_4 contains 3 moles of iron atom and 4 moles of oxygen atom

(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of Fe_3O_4

So, 247212 grams of iron will be produced from = \frac{231.53}{167.55}\times 247212=341611.43g of Fe_3O_4

To calculate the percentage of Fe_3O_4 in taconite, we use the equation:

\%\text{ composition of }Fe_3O_4=\frac{\text{Mass of }Fe_3O_4}{\text{Mass of taconite}}\times 100

Mass of taconite = 907185 g

Mass of Fe_3O_4 = 341611.43 g

Putting values in above equation, we get:

\%\text{ composition of }Fe_3O_4=\frac{341611.43g}{907185g}\times 100=37.6\%

Hence, the percent composition of Fe_3O_4 in taconite is 37.6 %.

8 0
3 years ago
Help can you match the answers to the definition PLZ Need this ASAP 30 points
Alchen [17]

Answer:

1-C

2-D

3-B

4-A

Explanation:

I think it is this if it is not , sorry!

8 0
3 years ago
...................................................................
neonofarm [45]

Answer:

Imao ;/

Explanation:

5 0
3 years ago
Read 2 more answers
Calculate the standard heat of reaction for the following methane-generating reaction of methanogenic bacteria: 4CH3NH2(g) + 2H2
PIT_PIT [208]

<u>Answer:</u> The standard heat for the given reaction is -138.82 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]

For the given chemical reaction:

4CH_3NH_2(g)+2H_2O(l)\rightarrow 3CH_4(g)+CO_2(g)+4NH_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(3\times \Delta H_f_{(CH_4(g))})+(1\times \Delta H_f_{(CO_2(g))})+(4\times \Delta H_f_{(NH_3(g))})]-[(4\times \Delta H_f_{(CH_3NH_2(g))})+(2\times \Delta H_f_{(H_2O(l))})]

We are given:

\Delta H_f_{(H_2O(l))}=-285.8kJ/mol\\\Delta H_f_{(NH_3(g))}=-46.1kJ/mol\\\Delta H_f_{(CH_4(g))}=-74.8kJ/mol\\\Delta H_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H_f_{(CH_3NH_2(g))}=-22.97kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(3\times (-74.8))+(1\times (-393.5))+(4\times (-46.1))]-[(4\times (-22.97))+(2\times (-285.8))]\\\\\Delta H_{rxn}=-138.82kJ

Hence, the standard heat for the given reaction is -138.82 kJ

3 0
3 years ago
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