First, we need to find the number of protons, which is the total mass divided by the mass of one proton:
protons
Then, the total charge is the number of protons times the charge of a single proton:
Answer:
True.
Explanation:
Don't turn wide to the left as you start the turn. A driver behind may think you are turning left and try to pass you on the right. You may crash into the other vehicle as you complete your turn.
Instead, slowly give yourself and others more time to avoid problems, keep the rear of the vehicle close to the curb. This will stop other drivers from passing you on the right. This is called (button Hook)
If you are driving a truck or bus that cannot make the right turn without swinging into the other lane, turn wide as you complete the turn.
The rocket will cover 
distance in 4. 5 s. Acceleration can be defined as the change in velocity.
<h3>
What is acceleration?</h3>
Acceleration can be defined as the change in speed or the direction of the object.
From kinamatic equation:
Where,
- final velocity = 445 m/s
- initial valocity = 0 m/s
- acceleration = 99. 0 m/s²
- time = 4. 50 s
Put the values in the formula,
Therefore, the rocket will cover distance in 4. 5 s.
Learn more about Acceleration :
brainly.com/question/2697545
Answer:
i)-6.25m/s
ii)18 metres
iii)26.5 m/s or 95.4 km/hr
Explanation:
Firstly convert 90km/hr to m/s
90 × 1000/3600 = 25m/s
(i) Apply v^2 = u^2 + 2As...where v(0m/s) is the final speed and u(25m/s) is initial speed and also s is the distance moved through(50 metres)
0 = (25)^2 + 2A(50)
0 = 625 + 100A....then moved the other value to one
-625 = 100A
Hence A = -6.25m/s^2(where the negative just tells us that its deceleration)
(ii) Firstly convert 54km/hr to m/s
In which this is 54 × 1000/3600 = 15m/s
then apply the same formula as that in (i)
0 = (15)^2 + 2(-6.25)s
-225 = -12.5s
Hence the stopping distance = 18metres
(iii) Apply the same formula and always remember that the deceleration values is the same throughout this question
0 = u^2 + 2(-6.25)(56)
u^2 = 700
Hence the speed that the car was travelling at is the,square root of 700 = 26.5m/s
In km/hr....26.5 × 3600/1000 = 95.4 km/hr
