Answer:
sorry i don't no
i promise i will help you later
now i am also in trouble now
nobody helps me
How does the angle of incoming light compare to the angle of light reflecting off of the surface?
- <em>The measurements of the angles are equal.</em>
<u>For</u><u> </u><u>a</u><u> </u><u>smooth</u><u> </u><u>surface</u><u>,</u><u> </u><u>The</u><u> </u><u>angle</u><u> </u><u>of</u><u> </u><u>reflection</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>angle</u><u> </u><u>of</u><u> </u><u>incidence</u><u> </u><u>are</u><u> </u><u>equal</u><u>.</u>
I think c Is the right answer or it could be b
Answer:
The angle with the positive x axis 61.31°
Explanation:
It is given that, a vector in the x-y plane has a magnitude of 25 m and x component of 12 m.
x component of the vector, base = 12 m
Magnitude of hypotenuse, H = 25 m
We need to find the angle with the positive x axis. Let it is given by θ such that :
θ = 61.31°
So, the angle with the positive x axis 61.31°. Hence, this is the required solution.