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lisabon 2012 [21]
2 years ago
8

A football is thrown with an acceleration of 15 m/s^2 and a force of 13 N. What is its mass?

Physics
2 answers:
-Dominant- [34]2 years ago
7 0
I believe it is b. Lmk if I’m wrong
nika2105 [10]2 years ago
7 0
B. 0.87 kg because 13 N and m/s^2
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Consider the displacement vectors Ā=(i +6j)m, B = (3i– 7j)m,
andrezito [222]

Answer:

Dx = -0.5

Dy = -0.25

Explanation:

Two vectors are given in rectangular components form as follows:

A = i + 6j

B = 3i - 7j

It is also given that:

A - B - 4D = 0

so, we solve this to find D vector:

(i + 6j) - (3i - 7j) - 4D = 0

- 2i - j = 4D

D = - (2/4)i - (1/4)j

D = - (1/2)i - (1/4)j

<u>D = - 0.5i - 0.25j</u>

Therefore,

<u>Dx = -0.5</u>

<u>Dy = -0.25</u>

8 0
3 years ago
A 48 kg cart is sitting motionless at the top of the hill. At what height, did the cart start at, to reach 88435 J of energy at
svet-max [94.6K]

Answer : The height is 188 meters  

Explanation :   When the cart reached at the end from top of hill then the cart have potential energy .

Given that,

Potential energy = 88435 J

Mass of cart = 48 kg

We know that,

The potential energy is

mgh =88435

h= \dfrac{88435}{48\times9.8}

h = 187.9 = 188\ meters

So, the height of the top is 188 meters.

7 0
3 years ago
Except when necessary for takeoff and landing, what is the minimum safe altitude required for a pilot to operate an aircraft ove
MAVERICK [17]
Except when necessary for takeoff and landing, <span>the minimum safe altitude required for a pilot to operate an aircraft over other than congested area is an altitude of 1000 ft above the highest obstacle within a 2000 ft horizontal radius of the aircraft.

It is also good to know that apart from taking off and landing, the aircraft must not operate at a distance less than 500 ft from any person, vessel, structure or vehicle.</span>
5 0
3 years ago
A general definition of media is "methods for communicating information." Please select the best answer from the choices provide
igor_vitrenko [27]

Answer:

A. True.

Explanation:

It['s true because the basic and general definition of media is "methods for communicating information".

6 0
3 years ago
A 79.7 kg base runner begins his slide into second base while moving at a speed of 4.77 m/s. The coefficient of friction between
SashulF [63]

To solve this problem we will apply the concept related to the kinetic energy theorem. Said theorem states that the work done by the net force (sum of all forces) applied to a particle is equal to the change experienced by the kinetic energy of that particle. This is:

\Delta W = \Delta KE

\Delta W = \frac{1}{2} mv^2

Here,

m = mass

v = Velocity

Our values are given as,

m = 79.7kg

v = 4.77m/s

Replacing,

\Delta W = \frac{1}{2} (79.7kg)(4.77m/s)^2

\Delta W = 907J

Therefore the mechanical energy lost due to friction acting on the runner is 907J

6 0
3 years ago
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