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3 years ago

A motorcyclist accelerates from rest to 10 mi/hr. what is the change in velocity

Physics

1 answer:

gulaghasi [49]3 years ago

6 0

The change in velocity is 10 mi/h (4.47 m/s)

Explanation:

The change in velocity of the motorcyclist is given by

$\Delta v = v-u$

where

v is the final velocity

u is the initial velocity

In this problem, we have

u = 0 (the motorbike starts from rest)

v = 10 mi/h

Therefore, the change in velocity is

$\Delta v = 10 -0 = 10 mi/h$

And keeping in mind that

1 mile = 1609 m

1 h = 3600 s

We can convert it into m/s:

$\Delta v = 10 \frac{mi}{h} \cdot \frac{1609 m/mi}{3600 s/h}=4.47 m/s$

Learn more about velocity:

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3 years ago

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Answer:

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Explanation:

By linear momentum conservation

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