Its durability, malleability, etc the basic properties of metals
The additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL
The moles of HCl which is required to reach the equivalence point can be calculated in the way as follows.
Moles of HCl can be calculated as
Moles of HCl = 0.004 moles of Ca (OH) 2 × 2 moles of HCl / 1 moles of Ca (OH) 2
= 0.008 moles of HCl
The volume of HCl which is required to reach the equivalence point can be calculated in the way given as follows.
Volume of HCl required= 0.008 moles of HCl × 1 L / 0.24 moles of HCl × 1 ml / 10 -³ L
= 33.33 ml
The additional volume of HCl calculated as
Additional volume = required volume – actual volume
= 33.33 mL – 25 mL
= 8 . 33 mL
Thus, we calculated that the additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL.
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To solve this problem, we need to set-up algebraic expression. First, use variables to represent the number of beads.
Let: x = number of Xavier's beads
y = number of Y<span>aozhou's beads
z = number of Zara's beads
</span>It is important to note that since we have three unknowns, we should also have three independent equations. <span>Based on the given statements, we have the following three equations:
(1) x + y = 438
(2) x + z = 204
(3) y = 3z
Substitute y in terms of z in equation (1). Then multiply equation (2) with -1.
x + 3z = 438
-(x + z = 204)
-------------------
2z = 234
z = 117
From equation (3),
y = 3(117) = 351
Using equation (1),
x = 438 - 351 = 87
Thus, Xavier had 87 beads.</span>
Answer:
Examples of isotones include carbon-12, nitrogen-13 and oxygen-14. These atoms all have six neutrons and six, seven and eight protons respectively. A mnemonic that can be used to differentiate isotones from isotopes and isobars is as follows: same Z (number of protons) = isotopes.
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