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grandymaker [24]
3 years ago
15

How do volcanoes change the Earth's surface?

Chemistry
2 answers:
icang [17]3 years ago
8 0
Hot ash, gases and molten rock pour out and destroy everything it touches and adding new rock where there was nothing before.
adelina 88 [10]3 years ago
6 0
When a volcano erupts magma comes from the top when the magma cools down it hardens and leaves a hard surface
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Which element is reduced in this reaction? cr2o72−+3hno2+5h+→2cr3++3no3−+4h2o enter the chemical symbol of the element?
Ksju [112]
<span>A reducing agent loses electrons, so on the left side of the equation N in HNO2 has an oxidation number of +3 and on the right side in NO3^- it has an oxidation number of +5, so it has lost electrons. Thus, the reducing agent would be HNO2.</span>
3 0
3 years ago
If earth is 1.50 x 10^8km from the sun what is the distance in Mm?
Readme [11.4K]

The distance of the earth to the sun in Mm = 1.5 x 10⁵

<h3>Further explanation</h3>

Given

The distance of the earth to the sun : 1.50 x 10⁸ km

Required

The distance in Mm

Solution

In converting units we must pay attention to the conversion factor.

the conversion factor :

1 kilometer(km) = 10⁻³ megameter(Mm)

So the distance conversion :

1.5 x 10⁸ x 10⁻³ = 1.5 x 10⁵ Mm

8 0
3 years ago
Write the following formulas in words:<br> a. НСІ<br> b. Naci
natka813 [3]

HCL:hydrochloric acid

Nacl:sodium chloride

8 0
3 years ago
Imagine that you run this experiment and that the initial change in pressure is 0.0023 atm/s. what is the initial reaction rate?
svet-max [94.6K]

\text{reaction rate} = 9.6 \times 10^{-5} \; \text{mol}\cdot\text{L}^{-1} \cdot \text{s}^{-1}

Explanation:

Concentration c = n / V;

The reaction see a 0.0023 \; \text{atm} change in pressure per second. By the ideal gas law, this quantity would correspond to a change in concentration, n/V of

c = n / V = P / (n \cdot R) = 0.0023 / ((273.15 + 20) \times 0.0821 ) = 9.6 \times 10^{-5} \; \text{mol}

where the ideal gas constant R = 0.0821 \; \text{L} \cdot \text{atm} \cdot \text{mol}^{-1} \cdot \text{K}^{-1}.

By definition, \text{reaction rate} = \Delta \text{concentration} / \Delta\text{time}

Therefore, for this particular reaction

\text{rate} = 9.6 \times 10^{-5} \; \text{mol} / (1 \; \text{s} ) = 9.6 \times 10^{-5} \; \text{mol}  \cdot \text{L}^{-1} \cdot \text{s}^{-1}

6 0
3 years ago
Cells take in small, energy-rich molecules from food. These molecules include sugar molecules. Cells use the molecules in a long
Solnce55 [7]

Answer:

1,2, and 3 are correct.

Explanation:

1 is true because cellular respiration begins in the cytoplasm of a cell. 2 is true because cellular respiration releases energy aerobically which uses glucose and oxygen or anaerobically which just uses glucose. Either way, energy is being released. 3 is true, I don't know how to explain why. Just keep the cellular respiration equation in mind, (C6H12O6 + 6O2 → 6CO2 + 6H2O + Chemical Energy (in ATP)), the chemical reactions are basically summed up into an equation. Hope that helped.

4 0
3 years ago
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