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baherus [9]
3 years ago
11

For the reaction represented by the equation cl2 + 2kbr ® 2kcl + br2, calculate the percentage yield if 200. g of chlorine react

with excess potassium bromide to produce 410. g of bromine.
Chemistry
1 answer:
alexgriva [62]3 years ago
5 0
The  %  yield if 200g   of chlorine  react  with  excess Potassium bromide to  produce  410g of  bromine  is calculated as below

%  yield =  actual  yield/theoretical yield  x100
the  actual yield = 410 grams

calculate the  theoretical yield
by first  calculate the moles of chlorine used

mole=  mass/molar  mass
molar  mass of Cl2 =  35.5 x2= 71 g/mol

moles=  200g/71g/mol  = 2.82  moles

cl2 +2 KBr = 2KCl  +Br2

by use  of mole ratio between Cl2  to Br2  which is 1:1  the  moles of  Br2 is also = 2.82  moles

theoretical  mass =  moles x molar mass
molar mass of Br2= 79.9 x2= 159.8 g/mol

moles= 2.82g x 159.8 g/mol = 450.64 grams

% yield is therefore = 410g/450.64 x100 = 90.98 %


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Charra [1.4K]

The major drawback of fossil fuels is that they warm the planet i.e. they cause global warming.

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                                  Fuel + O2 → CO2 + H2O + ENERGY

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7 0
1 year ago
Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 2
erastovalidia [21]

Answer:

Chloroform= limiting reactant

0.209mol of CCl4 is formed

And 32.186g of CCl4 is formed

Explanation:

The equation of reaction

CHCl3 + Cl2= CCl4 + HCl

From the equation 1 mol of

CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4

From the question

25g of CHCl3 really with Cl2

Molar mass of CHCl3= 119.5

Molar mass of Cl2 = 71

Hence moles of CHCl3= 25/119.5 = 0.209mol

Moles of Cl2 = 25/71 = 0.352mol

Hence CHCl3 is the limiting reactant

Since 1 mole of CHCl3 gave 1mol of CCl4

It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4

Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g

6 0
3 years ago
After the solution reaches equilibrium, what concentration of zn2 (aq remains?
Fantom [35]
According to sources, the most probable answer to this query is that when solutions reaches equilibrium, the amount of concentration of two or more matter combined in this solution becomes equal. 

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8 0
3 years ago
When copper metal is added to nitric acid, the following reaction takes place
zlopas [31]

Answer:

The volume of NO₂ gas collected over water at 25.0 °C is 1.68 Liters.

Explanation:

Cu (s) + 4 HNO_3 (aq) \rightarrow Cu(NO_3)_2 (aq) + 2 H_2O (l) + 2 NO_2 (g)

Moles of copper = \frac{2.01 g}{63.55 g/mol}=0.03163 mol

According to reaction, 1 mol of copper gives 2 moles of nitrogen dioxide gas.

Then 0.03613 moles of copper will give:

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Pressure of the gas = P

P = Total pressure - vapor pressure of water

P = 726 mmHg - 23.8 mmHg = 702.2 mmHg

P = 0.924 atm (1 atm = 760 mmHg)

Temperature of the gas = T = 25.0°C =298.15 K

Volume of the gas = V

PV=nRT

V=\frac{0.06326 mol\times 0.0821 atm L/mol K\times 298.15 K}{0.924 atm}

V = 1.68 L

The volume of NO₂ gas collected over water at 25.0 °C is 1.68 Liters.

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3 years ago
Mark the statement as true or false.
alex41 [277]

Answer:

False

Explanation:

The ideas were not proposed

3 0
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