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3 years ago

When the hydronium ion concentration equals 10 moles per liter, what is the ph of the solution? is the solution acidic or basic?

Chemistry

1 answer:

Nata [24]3 years ago

4 0

pH = - log[acid] = -log [H+]

pH= -log[10] = 1

Thus, pH is 1

if pH is 7, the solution is neutral and if pH is greater than 7 the solution is basic and if it is less than 7 the solution is acidic.

This solution have pH = 1, thus the solution is acidic.

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Now consider the reaction a+2b⇌c for which in the initial mixture qc=[c][a][b]2=387 is the reaction at equilibrium? if not, in w

Paul [167]

Solving this chemistry is a little bit hard because the question didn't give some important detailed.
So first, there are a couple problems with your question.
We will just need to know which direction will it proceed to reach equilibrium.
Your expression for Kc (and Qc ) for the reaction should be:
Kc = [C] / [A] [B]^2
You have not provided a value for Kc, so a value of Qc tells you absolutely nothing. Qc is only valuable in relation to a numerical value for Kc. If Qc = Kc, then the reaction is at equilibrium. If Q < K, the reaction will form more products to reach equilibrium, and if Q > Kc, the reaction will form more reactants.

5 0

3 years ago

In E. coli, the enzyme hexokinase catalyzes the reaction: Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Ke

kondor19780726 [428]

Answer:

Explanation:

Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Keq, is 7.8 x 102.

In the living E. coli cells,

[ATP] = 7.9 mM;

[ADP] = 1.04 mM,

[glucose] = 2 mM,

[glucose 6-phosphate] = 1 mM.

Determine if the reaction is at equilibrium. If the reaction is not at equilibrium, determine which side the reaction favors in living E. coli cells.

The reaction is given as

Glucose + ATP → glucose 6-phosphate + ADP

Now reaction quotient for given equation above is

$q=\frac{[\text {glucose 6-phosphate}][ADP]}{[Glucose][ATP]}$

$q=\frac{(1mm)\times (1.04 mm)}{(7.9mm)\times (2mm)} \\\\=6.582\times 10^{-2}$

so,

$q$ ⇒ following this criteria the reaction will go towards the right direction ( that is forward reaction is favorable until q = Keq

4 0

3 years ago

You are given sodium acetate, 1m hcl, nahco3 and na2co3. Determine which of these four you would need and then show calculations

valentina_108 [34]

solution:

the given compounds are sodium acetate, 1M HCL,NaHCO₃ and Na2CO₃

pH of the buffer solution is 4.7

the value of pKa of sodium bicarbonate is 6.37

the value of pKa of acetic acid is 4.7

calculate concentration of acetic acid by using the following forumula

pH=pKa+lag[salt]/[acid]

substitute the pH and Pka values in the formula.

4.7=4.7+log[salt]/[acid]

log[salt]/[acid]=0

thus, the concentration ratio of the salt and acid should be equal to each other.

Thus, concentration of sodium acetate is 0.05M

Concentration of sodium acetate= concentration of acid

= 0.05M

Volume of the buffer solution is 100mL

The buffer solution can be prepared as 0.05M of 50mL sodium acetate will react with 0.05M of 50mL of 0.05M of HCL.

The chemical equation for neutralization of the weak base with strong can be represented as show as

CH₃COONa+HCL-->CH₃COOH+NaCL

5 0

3 years ago

This is very difficult

Oliga [24]

Answer: C

Explanation:

6 0

3 years ago

Why are there 2 chloride ions for every 1 calcium in calcium chloride

tensa zangetsu [6.8K]

Answer:

See explanation

Explanation:

Calcium is divalent. This means that it donates two electrons during ionic bond formation. Since chlorine atom can only accept one electron during ionic bond formation, two chlorine atoms must accept the two electrons donated by calcium.

For this purpose, each time CaCl2 is formed, there must be two chlorine atoms for each calcium atom.

5 0

3 years ago