Answer:
the answer is 25.032g check pic for explanation
Answer:
C2H4Cl2
Explanation:
Firstly, we know that the compound contains only three elements. These are carbon, hydrogen and oxygen. We have the percentage compositions of carbon and hydrogen, thus we need the one for chlorine. To get the one for chlorine, we simply subtract that of carbon and hydrogen from a total of 100%.
Hence percentage composition of chlorine = 100 - 24.27 - 4.07 = 71.66%
Now, we divide the percentage compositions by the atomic masses. The atomic masses of carbon, hydrogen and chlorine are 12, 35.5 and 1 respectively. We go on to the divisions as follows.
C = 24.27/12 = 2.0225
H = 4.07/1 = 4.07
Cl = 71.66/35.5 = 2.02
We then go on to divide each by the smallest which is 2.02
C = 2.0225/2.02 = 1
H = 4.07/2.02 = 2
Cl = 2.02/2.02 = 1
Hence the empirical formula is CH2Cl
Now, since the molecular mass is 98.95, we need to calculate the molecular formula
Hence, [CH2Cl]n = 98.95
[12 + 2(1) + 35.5]n = 98.95
[12 + 2 + 35.5]n = 98.95
49.5n = 98.95
n = 98.95/49.5 = 2
The molecular formula is thus [CH2Cl]2 = C2H4Cl2
The value of Keq = 110
Let's know how to get it :
According to the equilibrium reaction equation :
I2(g) + Br2(g) → 2IBr(g)
now we need to get the value of Keq
when the Keq expression is:
Keq = [IBr]^2/ [I] [Br]
when we have [IBr] at equilibrium = 0.84 so we need to get [I] &[Br] at equilibrium .
when [Br2] = [I2] = 0.5 - 0.84 / 2
= 0.08 M
so, by substitution
∴ Keq = (0.84)^2/(0.08)^2
= 110
Answer:
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