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zimovet [89]
3 years ago
11

Which of the isomeric alcohols having the molecular formula c5h12o are chiral which are achiral?

Chemistry
2 answers:
Masteriza [31]3 years ago
7 0

Answer:

Chiral:

3-Methyl-2-butanol

Achiral:

1-Pentanol

3-Pentanol

3-Methyl-1-butanol

Explanation:

Only the molecule that bears a carbon atom surrounded by 4 different groups can be said to be Chiral, the other molecules don't satisfy this property.

Lunna [17]3 years ago
7 0

Answer:

C5H12O has <em>eight isomers</em>  

Chiral isomers are:  

Pentan-2-ol

2-Methylbutan-1-ol

3-Methylbutan-2-ol

Achiral isomers are:

Pentan-1-ol

Pentan-3-ol

3-Methylbutan-1-ol

3-Methylbutan-2-ol

2, 2-dimethylpropan-1-ol

Explanation:

C5H12O has eight isomers out of which three are chiral and five are achiral in nature

The isomers that have carbon atom(s) that are surrounded by four different groups are Chiral in nature while those that do not have such carbon atom(s) are achiral.  

Thus, only pentan-2-ol, 2-methylbutan-1-ol and 3-methylbutan-2-ol which have carbon atoms surrounded by four different groups are chiral. The carbon atom carrying the hydroxyl (-OH) group is the chiral carbon atom in these three isomers. While the carbon atoms in the other five isomers are achiral.

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Read 2 more answers
Be sure to answer all parts.
MrRissso [65]

Answer: The molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

Explanation:

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{28.5 g}{46 g/mol}\\= 0.619 mol

Now, molarity of ethanol solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.619 mol}{4.50 \times 10^{2} \times 10^{-3}L}\\= 1.38 M

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{21.6 g}{342.3 g/mol}\\= 0.063 mol

Now, molarity of sucrose solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.063 mol}{0.067 L}  (1 mL = 0.001 L)\\= 0.94 M

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

Moles = \frac{mass}{molar mass}\\= \frac{6.65 g}{58.44 g/mol}\\= 0.114 mol

Now, molarity of sodium chloride solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.114 mol}{0.0962 L}\\= 1.182 M

Thus, we can conclude that the molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

4 0
3 years ago
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