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zimovet [89]
2 years ago
11

Which of the isomeric alcohols having the molecular formula c5h12o are chiral which are achiral?

Chemistry
2 answers:
Masteriza [31]2 years ago
7 0

Answer:

Chiral:

3-Methyl-2-butanol

Achiral:

1-Pentanol

3-Pentanol

3-Methyl-1-butanol

Explanation:

Only the molecule that bears a carbon atom surrounded by 4 different groups can be said to be Chiral, the other molecules don't satisfy this property.

Lunna [17]2 years ago
7 0

Answer:

C5H12O has <em>eight isomers</em>  

Chiral isomers are:  

Pentan-2-ol

2-Methylbutan-1-ol

3-Methylbutan-2-ol

Achiral isomers are:

Pentan-1-ol

Pentan-3-ol

3-Methylbutan-1-ol

3-Methylbutan-2-ol

2, 2-dimethylpropan-1-ol

Explanation:

C5H12O has eight isomers out of which three are chiral and five are achiral in nature

The isomers that have carbon atom(s) that are surrounded by four different groups are Chiral in nature while those that do not have such carbon atom(s) are achiral.  

Thus, only pentan-2-ol, 2-methylbutan-1-ol and 3-methylbutan-2-ol which have carbon atoms surrounded by four different groups are chiral. The carbon atom carrying the hydroxyl (-OH) group is the chiral carbon atom in these three isomers. While the carbon atoms in the other five isomers are achiral.

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opper(I) ions in aqueous solution react with NH 3 ( aq ) according to Cu + ( aq ) + 2 NH 3 ( aq ) ⟶ Cu ( NH 3 ) + 2 ( aq ) K f =
Y_Kistochka [10]

Answer:

55.373g/l

Explanation:

The dissolved amount of sparingly soluble salts is interlinked with a unitlesss quantity called as solubility product. It is a fixed quantity that only increases with the rise in temperatures and is used to predict the salting out of compounds. If the value of ionic product (Q) is larger than (Ksp), precipitation of compound occurs.

Given:

The solubility product of CuBr is 6.3×10−9.

The concentration of NH3 is 0.10 M.

Formula and Calculations:

The dissolution reaction (I) of CuBr is shown below.

The reaction showing dissolution of CuBr in NH3 is shown below.

The above reaction can be obtained by adding reaction (I) and (II) as shown below.

The equilibrium constants will get multiplied.

Suppose the solubility of CuBr is “s”.

It is given that concentration of NH3 is 0.10 M.

The equilibrium constant expression for the above reaction is as follows,

Here,

The concentration of pure solids is 1 M. Thus, the concentration of CuBr is 1 M.

As calculated, the value of Ksp is 396.9.

Substitute all the required values in above formula.  

On further solving above equation,

Therefore, the solubility of CuBr in ammonia is 0.386 M.

The formula to calculate solubility

Solubuility (g/l)= Molarity(M) x Molarmass

Chemistry homework question answer, step 2, image 10

The molar mass of CuBr is 143.45 g/mol.

The formula to calculate solubility in g/L is given below.

The molar mass of CuBr is 143.45 g/mol.

therefore,

solubility = 0.386M x 143.45g/mol

where (M = mol/l)

solubility = 55.375g/l

5 0
3 years ago
6. What is the oxidation number for the atom indicated in the following compounds.
Hatshy [7]

Answer:

a. +6;

b. +5;

c. +3.

Explanation:

Start with elements with well-known oxidation states.

The oxidation state on oxygen O in compounds is mostly -2. Common exceptions include:

  • -1 in peroxides and
  • positive when oxygen bonds to fluorine.

The oxidation state on group 1 metals (Li, Na, K, etc.) in compounds is mostly +1.

The oxidation state on group 2 metals (Be, Mg, Ca, etc.) in compounds is mostly +2.

Barium Ba is a group 2 metal. The oxidation state on Ba in the compound BaSO₄ is expected to be +2.

The oxidation state on hydrogen H in compounds is mostly +1. The oxidation state on H might be negative when it is bonded to metals.  

The oxidation state on halogens (F, Cl, Br, etc.) is mostly -1. The oxidation state may vary when the halogen is bonded to oxygen or another halogen element.

Compounds are neutral. The oxidation state on all atoms in a compound shall add up to 0. Both BaSO₄ and HClO₂ are neutral.

<h3>BaSO₄</h3>

Oxidation states:

  • Ba: +2;
  • The oxidation state on sulfur S is to be determined;
  • O: -2.

Let the oxidation state on S be x.

2 + x + 4 × (-2) = 0;

x = 6.

Hence, the oxidation state on S in BaSO₄ is +6.

<h3>HClO₂</h3>

Oxidation states:

  • H: +1;
  • Cl here is bonded to oxygen. The oxidation state on chlorine Cl is to be determined;
  • O: -2.

Let the oxidation state on Cl be x.

<em>Refer to the equation in BaSO₄ as an example. Try setting up the equation on your own. </em>

x = 3.

Hence, the oxidation state on Cl is +3.

<h3>PO₄³⁻</h3>

Ions carry charge. Oxidation states on atoms in an ion shall add up to the charge of the ion. The superscript of an ion shows its charge. The superscript 3- in the phosphate ion shows that the ion carries a charge of -3.

Oxidation states:

  • The oxidation state on P is to be found;
  • O: -2.

Let the oxidation state on P be x.

x + 4 × (-2) = -3;

x = 5.

Hence, the oxidation state on P is +5.

4 0
3 years ago
HELP ME PLEASE!! If given a graduated cylinder, a beaker with alcohol and a scale, explain the steps to find the mass of 40 mL o
Luda [366]
<h3>Further explanation </h3>

In general, some people equate mass and weight.

Mass is one of the principal quantities, which is related to the matter , whereas weight is a force that leads to the center of the earth (Earth's gravitational force)

Steps that can be taken  to find the mass :

  • 1. Weigh graduated cylinder (empty)
  • 2. Pour the alcohol in the beaker into the graduated cylinder to the level of 40 ml
  • 3. Weigh again graduated cylinder + poured alcohol
  • 4. mass of alcohol 40 ml = mass in 3rd step - mass in the first step

6 0
3 years ago
What is the final concentration (M) of a solution prepared by diluting 50.0 mL of a solution to a volume of
docker41 [41]
0.600
D) 0.600 is the final concentration of the solution of KCl.
V1 = 50.0 mL.
6 0
2 years ago
A patient needs to take 875mg twice daily The pills in the bottle are each 250mg How many pills does she wants to take 875mg
Angelina_Jolie [31]

Answer:

3.5 pill need to taken for completing dosage of 875 mg

Explanation:

Total dosage of medicine to be taken in a day

= 2 * 875 \\= 1750mg

Total weight of one pill = 250 mg

Number of pills required is equal to total dosage of medicine divided by the weight of one pill.

Hence,

Number of pills

= \frac{875}{250} \\= \frac{175}{50} \\= \frac{35}{10} \\= 3.5

6 0
3 years ago
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