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Romashka-Z-Leto [24]
3 years ago
15

Two stones resembling diamonds are suspected of being fakes. To determine if the stones might be real, the mass and volume of ea

ch are measured. Both stones have the same volume, 0.15 cm^3. However, stone A has a mass of 0.52 g, and stone B has a mass of 0.42 g.
A) If diamond has a density of 3.5 g/cm^3, could either of the stones be real diamonds? Explain.
Chemistry
1 answer:
Charra [1.4K]3 years ago
4 0

Answer:

Stone A

Explanation:

Measuring density is an easiest way to determine if two similar looking substances are same or not. Here also we need to perform the density test for each stone that is suspected to be fake diamond. We will calculate the density of each stone and compare it with the density of original diamond.

Density is calculated using the formula

Density=\frac{Mass}{Volume}

It has been given in the question that both the substances have same volume of 0.15 cm^3.

Density of stone A = \frac{0.52}{0.15} = 3.47 gcm^-^3 or after rounding off we get 3.5 gcm^-^3

Density of stone B = \frac{0.42}{0.15} = 2.8 gcm^-^3

It is clear from the above calculation that the stone A has same density as the diamond but stone B lacks behind in density.

So, stone A could be the real diamond.

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Calculate the mass of ethyl alcohol required to prepare 540 grams of C4H6, if the reaction follows the scheme:
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Explanation:

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2 mole               1 mole

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A ball is equipped with a speedometer and launched straight upward. The speedometer reading four seconds after launch is shown a
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Answer:

Question 1: <u>1 s after the motion starts</u>

Question 2: <u>0 (just when the motion starts)</u>

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You will need to work with approximates values because the precision of the speedometers is low and you are requested to find approximate times.

<u>1. From the speedometer shown at the right.</u>

You can obtain how long the ball has been falling from the highest altitute it reached using the speed of 10 m/s shown by the speedometer at the right.

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  • Vo = 0 ⇒ Vf = gt ⇒ t = Vf / g

For this problem, I recommend to work with a rough estimate of g: g = 10 m/s² ( I will tell you why soon)/

  • t = [10 m/s] / [10 m/s²] = 1 s

That is the time falling. Since four seconds after launch have elapsed, the upward time was 3 seconds. This will let you to calculate the launching speed.

<u>2. Time when the speedometer displays a reading of 20 m/s</u>

First, calculate the launching speed:

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Since the ball was 3 seconds going upward and the speed at the maximum altitude is 0 you get:

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Now, use the initial velocity to calculate when the ball is going upward with the speedometer reading is 20 m/s

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Thus, the first answer is t = 1 s.

<u />

<u>3. Time when the speedometer displays a reading of 30 m/s</u>

This is the same speec estimated for the launching: 30 m/s.

So, this reading corresponds to the moment when the ball was launched.

Thus time is 0, i.e. it is the same instant of the launch.

If you had worked with g = 9.80 m/s², the time had been negative. This is due to the precision of the instruments.

That is why I recommended to work with g = 10 m/s².

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