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Maksim231197 [3]
2 years ago
13

An ionic compound has a solubility of 30 g per 100 mL of water at room temperature. A solution containing 70 g of the compound i

n 300 mL of water at the same temperature is:
A. unsaturated.
B. saturated.
C. a suspension.
D. supersaturated.
Chemistry
1 answer:
Llana [10]2 years ago
3 0

Answer: A. unsaturated.

Explanation:

Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

Supersaturated solution is defined as the solution in which more amount of solute particles is present than the solvent particles.

Given:  Solubility = 30g/100ml

If 100 ml can dissolve ionic compound = 30 g

300 ml can dissolve ionic compound  =\frac{30}{100}\times 300=90g

Thus solubility is 90g/300 ml and dissolved salt is only 70 g , the solution is said to be unsaturated.

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Why does a pan of warm water eventually become the same temperature as the room it is in
rewona [7]
the room will either cool down or warm up the water until it is the same temperature as the room around it.
4 0
3 years ago
The chemistry lab is 0.3394km from the nurses office. How many feet is the distance?
nlexa [21]
Easy just convert it to feet the answer is <span>1113.51706 Feet

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6 0
3 years ago
What is the mass (in grams) of 9.79 × 1024 molecules of methanol (CH3OH)?
nevsk [136]
We will use this formlula: Mass in grams = Number of moles x Molecular mass of 1 mole.

Since, we know the avagadro number is 6.02 x 10²³, we only have two unknown values left which are the molecular mass of CH3OH and its mole.

Molecular Mass: C = 12, H= 1, O = 16, since we have C=12, H4 = 4, O = 16, we will add them up: 12 + 4 + 16 =32

We know that one mole of anything = 6.02 x 10²³.
So we will use this formula to find the mole of methanol: Number of moles = Number of molecules / Avagadro number

Number of moles of CH3OH = (9.79 x 10^24)/6.02 x 10²³) =  16.263 moles.

Now we know that the molecular mass = 32 and the mole is = 16.263.

Now we can find its mass by using this formula: <span>Mass in grams = Number of moles x Molecular mass of 1 mole.
</span>
Mass in grams = 16.263 x 32 = 520g






6 0
3 years ago
The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mas
Roman55 [17]

Answer:

Mass, m = 1.51 grams

Explanation:

It is given that,

The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm

Length of the cylinder, h = 4.2 cm

We know that the density of the Aluminium is 2.7 g/cm³

Circumference, C = 2πr

r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm

Density is equal to mass per unit volume.

d=\dfrac{m}{V}

m is mass of the cylinder

V is the volume of the cylinder

V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3

So,

m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g

So, the mass of the cylinder is 1.51 grams.

5 0
3 years ago
What is the concentration of a sodium hydroxide solution if 14.5 mL of it are exactly neutralized by 30.0 mL of a 0.500 M hydroc
rusak2 [61]

Answer:

1.03 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

30.0 mL (0.0300 L) of 0.500 M HCl react.

0.0300 L × 0.500 mol/L = 0.0150 mol

Step 3: Calculate the moles of NaOH that react with 0.0150 moles of HCl

The molar ratio of NaOH to HCl is 1:1. The moles of NaOH that react are 1/1 × 0.0150 mol = 0.0150 mol.

Step 4: Calculate the molar concentration of NaOH

0.0150 moles of NaOH are in 14.5 mL (0.0145 L).

M = 0.0150 mol/0.0145 L = 1.03 M

4 0
3 years ago
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