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Maksim231197 [3]
3 years ago
13

An ionic compound has a solubility of 30 g per 100 mL of water at room temperature. A solution containing 70 g of the compound i

n 300 mL of water at the same temperature is:
A. unsaturated.
B. saturated.
C. a suspension.
D. supersaturated.
Chemistry
1 answer:
Llana [10]3 years ago
3 0

Answer: A. unsaturated.

Explanation:

Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

Supersaturated solution is defined as the solution in which more amount of solute particles is present than the solvent particles.

Given:  Solubility = 30g/100ml

If 100 ml can dissolve ionic compound = 30 g

300 ml can dissolve ionic compound  =\frac{30}{100}\times 300=90g

Thus solubility is 90g/300 ml and dissolved salt is only 70 g , the solution is said to be unsaturated.

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3 years ago
A certain radioactive nuclide has a half life of 1.00 hour(s). Calculate the rate constant for this nuclide. s-1 Calculate the d
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Explanation:

From the information provided;

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8 0
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If an ideal gas has a pressure of 5.49 atm, a temperature of 88.78 °c, and has a volume of 22.03 l, how many moles of gas are in
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N = (PV)/RT
(T = 88.78 + 273 = 361.78K)
(R = 22.4/273 = 0.082)
= (5.49 x 22.03)/(0.082 x 361.78) = ?
Put it into the calculator. It's hard to do that on a mobile phone.
7 0
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