This is a plain and simple answer. No distributive property here!
68 ÷ 4 = 17
Answer:
![\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%5Cfrac%7B3%5Cpi%7D%7B2%7D%5Cfrac%7B2%5Cpi%7D%7B3%7D%5Cfrac%7B4%5Cpi%7D%7B3%7D)
Step-by-step explanation:
You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.
You will find when you look on your trig identity sheet that
![cos(2\theta)=1-2sin^2(\theta)](https://tex.z-dn.net/?f=cos%282%5Ctheta%29%3D1-2sin%5E2%28%5Ctheta%29)
so we will make that replacement, getting everything in terms of sin:
![sin(\theta)+1=1-2sin^2(\theta)](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%2B1%3D1-2sin%5E2%28%5Ctheta%29)
Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:
![2sin^2(\theta)+sin(\theta)=0](https://tex.z-dn.net/?f=2sin%5E2%28%5Ctheta%29%2Bsin%28%5Ctheta%29%3D0)
We can factor out the sin(theta), since it's common in both terms:
![sin(\theta)(2sin(\theta)+1)=0](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%282sin%28%5Ctheta%29%2B1%29%3D0)
Because of the Zero Product Property, either
or
![2sin(\theta)+1=0](https://tex.z-dn.net/?f=2sin%28%5Ctheta%29%2B1%3D0)
Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:
![\theta=\frac{\pi}{2},\frac{3\pi}{2}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%5Cfrac%7B3%5Cpi%7D%7B2%7D)
The next equation needs to first be solved for sin(theta):
so
and
![sin(\theta)=-\frac{1}{2}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D-%5Cfrac%7B1%7D%7B2%7D)
Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:
![\theta=\frac{2\pi}{3},\frac{4\pi}{3}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Cfrac%7B2%5Cpi%7D%7B3%7D%2C%5Cfrac%7B4%5Cpi%7D%7B3%7D)
Its solved already??any more questions just ask me:)
Answer:
1 kiloliter
Step-by-step explanation: