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timofeeve [1]
3 years ago
6

Based on the balanced chemical equation shown below, determine the mass percent of fe3+ in a 0.strings_1450g sample of iron ore,

if 22.40 ml of a 0.1000 m stannous chloride, sncl2(aq), solution is required to completely react with the fe3+ present in the ore sample. the chemical equation for the reaction is 2 fe3+(aq) + sn2+(aq) → 2 fe2+(aq) + sn4+(aq).
Chemistry
1 answer:
IRINA_888 [86]3 years ago
5 0
I think there is a mistake in strings mass, I think it is 0.7450 g, not 0.1450 g
First, we need to get no.of moles of SN2+ = molarity * volume

= 0.1 M* 0.0224 L = 0.00224 moles 

So, according to the reaction equation:

2Fe3+(aq)  +  SN2+(aq) → 2 Fe2(aq) + SN4+ (Aq)

we can see that the molar ratio between Fe3+ and SN2+ = 2:1

∴ to get the no.of moles Fe3+ we have to multiply SN2+ by 2
= 2 * 0.00224 = 0.00448 moles 

now, when we know the molar mass of  Fe3+ = 55.847 g/mol

so, we can use it and the no. of moles to get the mass

mass Fe3+ =  moles * molar mass
                   = 0.00448 * 55.847 = 0.25 g

∴ Mass Fe3+ % = 0.25/0.7450 * 100 = 33.6 %
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2 H2S(g) ⇄ 2 H2(g) + S2(g) Kc = 9.3× 10-8 at 400ºC 0.47 moles of H2S are placed in a 3.0 L container and the system is allowed t
Anon25 [30]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

<u>Explanation:</u>

We are given:

Initial moles of hydrogen sulfide gas = 0.47 moles

Volume of the container = 3.0 L

The molarity of solution is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of the solution}}

So, \text{Initial molarity of hydrogen sulfide gas}=\frac{0.47}{3}=0.1567M

The given chemical equation follows:

                          2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

<u>Initial:</u>                  0.1567

<u>At eqllm:</u>           0.1567-2x       2x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

We are given:

K_c=9.3\times 10^{-8}

Putting values in above equation, we get:

9.3\times 10^{-8}=\frac{(2x)^2\times x}{(0.1567-2x)^2}\\\\x=8.24\times 10^{-4}

So, equilibrium concentration of hydrogen gas = 2x=(2\times 8.24\times 10^{-4})=1.648\times 10^{-3}M

Hence, the concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

7 0
3 years ago
In carbon dioxide (CO2), how many grams of oxygen (O) would there be if there are 24 grams of carbon (C)?
Zarrin [17]

Answer:

64g of Oxygen

Explanation:

Firstly, carbon and oxygen react to form CO2 as follows;

C + O2 => CO2

According to the equation, one mole of C reacts with one mole of O2 to give one mole of CO2

Since molar mass of C= 12g/mol, O= 16g/mol

One mole of (C) contains 12g

One mole of O2 contains 16(2) = 32g

Hence, If there are 24g of C, there would be 24 × 32 / 12

= 768/12

= 64g

Hence, there would be 64g of oxygen if there are 24g of Carbon

6 0
4 years ago
I am trying to figure out what blood type the father of my son could have since my son and I are both type A. Also, my brother i
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Answer:

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Explanation:

Just like eye or hair color, our blood type is inherited from our parents. Each biological parent donates one of two ABO genes to their child. The A and B genes are dominant and the O gene is recessive. For example, if an O gene is paired with an A gene, the blood type will be A.

6 0
3 years ago
If a trait varies greatly within a pair of identical twins, it is most likely caused by what?
notsponge [240]

Answer:

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Explanation:

6 0
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2. What if hydrogen were left over?
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Answer: limiting reactant (or limiting reagent): The reactant that determines the amount of product that can be formed in a chemical reaction.

Explanation: Your welcome buddy.

5 0
2 years ago
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