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Volgvan
4 years ago
9

In carbon dioxide (CO2), how many grams of oxygen (O) would there be if there are 24 grams of carbon (C)?

Chemistry
1 answer:
Zarrin [17]4 years ago
6 0

Answer:

64g of Oxygen

Explanation:

Firstly, carbon and oxygen react to form CO2 as follows;

C + O2 => CO2

According to the equation, one mole of C reacts with one mole of O2 to give one mole of CO2

Since molar mass of C= 12g/mol, O= 16g/mol

One mole of (C) contains 12g

One mole of O2 contains 16(2) = 32g

Hence, If there are 24g of C, there would be 24 × 32 / 12

= 768/12

= 64g

Hence, there would be 64g of oxygen if there are 24g of Carbon

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What is the molarity of a solution made with 400 grams of copper II chloride in 3.5 liters of water?
Leni [432]

Answer:

0.85M

Explanation:

Given parameters:

Mass of CuCl₂  = 400g

Volume of water  = 3.5L

Unknown:

Molarity of the solution = ?

Solution:

Molarity is one of the ways of expressing the concentrations of a solution. It is defined as the number of moles per unit volume of a solvent.

          Molarity  = \frac{number of moles}{volume}

To find the number of moles of CuCl₂;

    Number of moles  = \frac{mass}{molar mass}

  Molar mass of CuCl₂ = 63.6 + 2(35.5)  = 134.6g/mol

   Number of moles  = \frac{400}{134.6}   = 2.97moles

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Explanation:

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The halogens, the elements of Family 17 on the periodic table, combine easily with elements from Family 1. When a halogen reacts
timofeeve [1]

Answer:

When halogen elements react with group one metals they form halide salts.

Explanation:

The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Halogens are very reactive these elements can not be found free in nature. Their chemical properties are resemble greatly with each other. As we move down the group in periodic table size of halogens increases that's way fluorine is smaller in size as compared to other halogens elements. Their boiling points also increases down the group which changes their physical states. i.e fluorine is gas while iodine is solid.

When halogen elements react with group one metals they form halide salts.

Alkali metals have one valance electron and halogens needed one electron to complete the octet thus alkali metals loses one electron which is accepted by halogens atom and form ionic compound called halide salts.

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2Rb + Cl₂ → 2RbCl

2Li + Cl₂ → 2LiCl

With bromine:

2Na + Br₂ → 2NaBr

2K + Br₂  → 2KBr

2Rb + Br₂ → 2RbBr

2Li + Br₂ → 2LiBr

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2Na + I₂ → 2NaI

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2Rb + I₂ → 2RbI

2Li + I₂ → 2LiI

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3 years ago
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