Answer:
it would have potential energy
Answer:
51.96 m/s^-1
Explanation:
a) see the attachment
b) As we know the velocity of the projectile has two component, horizontal velocity v_ox. and vertical velocity v_oy as shown in the figure. At the highest point of the trajectory, the projectile has only horizontal velocity and vertical velocity is zero. Therefore at the highest point of the trajectory, the velocity of the projectile will be
v_ox=v_o*cosФ
=60*cos (30)
= 51.96 m/s^-1
Velocity of an object is its rate of change of the object's position per interval of time. Velocity is a vector quantity which means that it consists of a magnitude and a direction. Magnitude is represented by the speed and the direction is represented by the angle. To determine the velocity components, we use trigonometric functions to determine the angle of the components. For the north component we, use the sine function while, for the west component, we use the cosine function. We calculate as follows:
north velocity component = (16.8 m/s) (sin 54°) = 16.4 m/s
<span>west velocity component = (16.8 m/s) (cos 54°) = 3.49 m/s</span>
Explanation:
It is given that,
Let Charge of
is taken from points A & B such that
.
We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,

So, the energy of charge decreases by
. Hence, the correct option is (a).
Answer:
north direction.
Explanation:
The wire carries a current towards the east . The magnetic field will make circular path around the wire in clockwise direction so at a point just south of wire , magnetic field will be into the plane of paper containing wire. If we take east as x -axes , north as y axes then out of plane will form z axes. Hence direction of magnetic field will be - z direction .
Magnetic field can be represented as - B k
Proton is moving towards east ie in + x direction so it can be represented as follows
velocity = V i
Force F = q( V i x -B k)
= ( BqV) j or + ve j direction or along north direction
So direction of force will be along north direction.