Question

Which states of a hydrogen atom can be excited by a collision with an electron with kinetic energy k = 12. 5 ev?

Answer 1

The answer is the  excited state of the hydrogen atom, n=24 and Z=23

Kinetic energy of electron is, $\mathrm{KE}=\frac{13.6 \mathrm{Z}^{2}}{\mathrm{n}^{2}} \mathrm{eV}$

For  the  excited state of the hydrogen atom , n=24 and Z=23

K.E=$\frac{13.6 \times 23^{2}}{24^{2}}=$12.5

What is the hydrogen atom?

• The hydrogen atom is the most basic of all the atoms since it just has one proton and one electron.
• There are two more hydrogen isotopes, deuterium and tritium, in addition to protium, which is the most prevalent form of the atom.
• The hydrogen atom consists of a proton and an electron, and has a spherical symmetry that can most easily be studied using a spherical polar coordinate frame.

To learn more about hydrogen atom  visit: brainly.com/question/1462347?

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