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densk [106]
2 years ago
6

Which states of a hydrogen atom can be excited by a collision with an electron with kinetic energy k = 12. 5 ev?

Physics
1 answer:
Sophie [7]2 years ago
5 0

The answer is the  excited state of the hydrogen atom, n=24 and Z=23

Kinetic energy of electron is, $\mathrm{KE}=\frac{13.6 \mathrm{Z}^{2}}{\mathrm{n}^{2}} \mathrm{eV}$

For  the  excited state of the hydrogen atom , n=24 and Z=23

K.E=\frac{13.6 \times 23^{2}}{24^{2}}=12.5

What is the hydrogen atom?

  • The hydrogen atom is the most basic of all the atoms since it just has one proton and one electron.
  • There are two more hydrogen isotopes, deuterium and tritium, in addition to protium, which is the most prevalent form of the atom.
  • The hydrogen atom consists of a proton and an electron, and has a spherical symmetry that can most easily be studied using a spherical polar coordinate frame.

To learn more about hydrogen atom  visit: brainly.com/question/1462347?

#SPJ4

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(a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward f
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What evidence supports the conclusion that a chemical reaction has occurred?
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A particle moves in a straight line with the velocity function v ( t ) = sin ( w t ) cos 3 ( w t ) . find its position function
Sunny_sXe [5.5K]

Integrating the velocity equation, we will see that the position equation is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

<h3>How to get the position equation of the particle?</h3>

Let the velocity of the particle is:

$v(t)=\sin (\omega t) * \cos ^2(\omega t)

To get the position equation we just need to integrate the above equation:

$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t

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Replacing that in our integral we get:

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Where C is a constant of integration.

Now we remember that $u=\cos (\omega t)$

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$f(t)=\frac{\cos ^3(\omega t)-1}{3}

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