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2 years ago

Which states of a hydrogen atom can be excited by a collision with an electron with kinetic energy k = 12. 5 ev?

Physics

1 answer:

Sophie [7]2 years ago

5 0

The answer is the excited state of the hydrogen atom, n=24 and Z=23

Kinetic energy of electron is, $\mathrm{KE}=\frac{13.6 \mathrm{Z}^{2}}{\mathrm{n}^{2}} \mathrm{eV}$

For the excited state of the hydrogen atom , n=24 and Z=23

K.E= $\frac{13.6 \times 23^{2}}{24^{2}}=$ 12.5

What is the hydrogen atom?

The hydrogen atom is the most basic of all the atoms since it just has one proton and one electron.
There are two more hydrogen isotopes, deuterium and tritium, in addition to protium, which is the most prevalent form of the atom.
The hydrogen atom consists of a proton and an electron, and has a spherical symmetry that can most easily be studied using a spherical polar coordinate frame.

To learn more about hydrogen atom visit: brainly.com/question/1462347?

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Answer: Force I believe.

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2 years ago

Boyle's law balloon was filled to a volume of 2.50 l when the temperature was 30.0∘

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To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

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2 years ago

En que parte de la isla de cuba tuvieron lugar los principales acontecimientos de la guerra de independencia?

DedPeter [7]

Answer:

El 24 de febrero de 1895, por órdenes de Martí se levantan 35 aldeas en el Oriente de Cuba en lo que se ha dado en llamar el Grito de Baire.

Entre los lugares están Ibarra, Guantánamo y Manzanillo.

Explanation:

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3 years ago

A 5.0-kg rock and a 3.0 × 10−4-kg pebble are held near the surface of the earth.(a)Determine the magnitude of the gravitational

a_sh-v [17]

Answer:

a). Determine the magnitude of the gravitational force exerted on each by the earth.

Rock: $F = 49.06N$

Pebble: $F = 29.44N$

(b)Calculate the magnitude of the acceleration of each object when released.

Rock: $a =9.8m/s^{2}$

Pebble: $a =9.8m/s^{2}$

Explanation:

The universal law of gravitation is defined as:

$F = G\frac{m1m2}{r^{2}}$ (1)

Where G is the gravitational constant, m1 and m2 are the masses of the two objects and r is the distance between them.

Case for the rock $m = 5.0 Kg$ :

m1 will be equal to the mass of the Earth $m1 = 5.972×10^{24} Kg$ and since the rock and the pebble are held near the surface of the Earth, then, r will be equal to the radius of the Earth $r = 6371000m$ .