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Alja [10]
3 years ago
12

A snowball that will be used to build a snowman is at the top of a only hill. If the

Physics
1 answer:
Darina [25.2K]3 years ago
5 0

Answer:

h = 24.11 m

Explanation:

Given that,

The potential energy of the snowball is 520 J

The mass of the snowball is 2.2 kg

We need to find the height of the hill. The potential energy of an object is given by the formula as follows :

E=mgh

g is acceleration due to gravity

h is height of the hill

h=\dfrac{E}{mg}\\\\h=\dfrac{520}{2.2\times 9.8}\\\\h=24.11\ m

So, the height of the hill is 24.11 m.

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The greater the mass of an object.
yKpoI14uk [10]

Answer:

Mass is the measure of an object's matter (what it's made up of). The greater an object's mass, the greater its gravitational force. The earth has a strong attracting force for objects with smaller mass (including the moon), and the sun has an attracting force on the earth and other planets in our solar system.

7 0
3 years ago
Read 2 more answers
1 question, brainliest for whoever gets it right.
Kaylis [27]

Answer:

im pretty sure the answer is c please mark me brainliest

6 0
3 years ago
There are 640 acres in a square mile. how many square meters are there in 7.80 acres.
lukranit [14]

Answer:

On 7.8 acres there are 31565.3 square meters

7.8 acres = 31565.3 m²

Explanation:

Conceptual analysis

Acre, square mile and square meter are area units, so their equivalences are in square units.

Known data

1 (mi)² = 640 acres

1 mi = 1609.34 m

Problem development

We know that 1 mile = 1609.34m, then: (1 mile)² = (1609.34m)²=(1609.34)²m²

We apply the known conversion factors to calculate the square meters (X) in 7.8 acres:

X=7.8 acres *\frac{(1 mi)^{2} }{640 acres} * \frac{(1609.34)^{2}m^{2}  }{(1 mi)^{2} }

We eliminate acres and square miles (mi²) because they are in the numerator and denominator, so the answer is in square meters (m²)

X=31565.3 m²

On 7.8 acres there are 31565.3 square meters

7.8 acres = 31565.3 m²

8 0
3 years ago
Please help on this one?
lisov135 [29]

Answer:

The current in a resistor decreases by a factor of 4.

Explanation:

I = \frac{E}{R}

Where (I) is the current, (E) is the voltage and (R) is the resistance.

Decreasing the voltage by 4 gives;

I = 0.25\frac{E}{R}

Since you have multiplied \frac{E}{R} by 0.25,

You have to multiply I by 0.25 so the current decreases by a factor of 4.

3 0
3 years ago
What percentage of the power of the battery is dissipated across the internal resistance and hence is not available to the bulb?
spin [16.1K]

Lets us consider an example:


Suppose a 10 ohm bulb is connected across the terminals of a 10 V

battery having 2ohm internal resistance.

Then total reistance in series we know, R1 + R2 

Thus, R net = 10+ 2 = 12 ohm

The, current across circuit = 10/12= 0.833 A

Now, Power is given by P = i^{2} R \\ \\

Thus, power dissipated across internal resistance, P = 0.83^{2} * 2 = 1.37 Watt

And, total power dissipated =0.83^{2} * 12 = 8.2 watt

Thsu, percentage of pwer not avaible = 1.37/8.2 = 16.70%

5 0
4 years ago
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