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photoshop1234 [79]
3 years ago
8

Is diet Pepsi heterogeneous or is it homogeneous

Physics
2 answers:
Lana71 [14]3 years ago
6 0
Heterogeneous because it has less amount of sugar than the regular Pepsi has
Aleks04 [339]3 years ago
3 0
It is of no use normal pepsi testes way better have that only i am experianed totally
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A car advertisement claims their car can go from a stopped position to moving 60 miles per hour in 5 seconds. The advertisement
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It is more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity. This is beca
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Answer:

d. the coefficient of static friction is greater than the coefficient of kinetic friction.

Explanation:

The magnitude of the for required to be applied to the carton is given as equal to the frictional force of between the carton and the surface. So, when the carton is at rest:

F = μs*W

and when the carton is in motion:

F = μk*W

where,

F = Force Required

μs = coefficient of static friction

μk = coefficient of kinetic friction

W = Weight of Carton

Since, the weight is constant. Therefore, for the increase in the force required to move the carton at rest than the force required to keep pushing the carton in velocity, the coefficient of static friction must be greater than the coefficient of kinetic friction. Therefore, the correct option is:

<u>d. the coefficient of static friction is greater than the coefficient of kinetic friction.</u>

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2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Why does the apple look red?
Ierofanga [76]

It is B

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3 years ago
An electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direc
levacccp [35]

Complete question:

An electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +6.18 x 105 m/s to a final velocity of 2.59 x 106 m/s while traveling a distance of 0.0708 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 8.87 x 10-17 N, and , which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F₂.

Answer:

(a) The net force of the electron, ∑F = 4.07 x 10⁻¹⁷ N

(b) the electric force, F₂ = 4.8 x 10⁻¹⁷ N

Explanation:

Given;

initial velocity of the electron, v_0 = +6.18 x 10⁵ m/s

final velocity of the electron, v_f = 2.59 x 10⁶ m/s

the distance traveled by the electron, d = 0.0708 m

The first electric force, F_1 = 8.87*10^{-17} \ N

(a) The net force of the electron is given as;

∑F = F₁ - F₂ = ma

where;

a is the acceleration of the electron

a = \frac{v_f^2 -v_0^2}{2d} \\\\a = \frac{(2.59*10^6)^2 -(6.18*10^5)^2}{2(0.0708)}\\\\a = 4.468*10^{13} \ m/s^2

∑F = ma = (9.11 x 10⁻³¹ kg)(4.468 x 10¹³)

∑F = 4.07 x 10⁻¹⁷ N

(b) the electric force, F₂ is given as;

∑F = F₁ - F₂

F₂ = F₁ - ∑F

F₂ = 8.87 x 10⁻¹⁷ - 4.07 x 10⁻¹⁷

F₂ = 4.8 x 10⁻¹⁷ N

5 0
3 years ago
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