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KatRina [158]
3 years ago
8

45. The following data was collected for 3 compounds:

Chemistry
1 answer:
Vika [28.1K]3 years ago
5 0

Answer:

The three compounds are different compounds

Explanation:

The mass of Nitrogen that combines with 1 gram of Oxygen in  Compound A = 1.750 g

The mass of Nitrogen that combines with 1 gram of Oxygen in  Compound B  = 0.8750 g

The mass of Nitrogen that combines with 1 gram of Oxygen in  Compound C  = 0.4375 g

According to the law of multiple proportions, when atoms of two different elements react to form compounds, the masses of one of the elements that combines with a fixed mass of the other element are in small whole number ratios.

The ratio of the masses are;

Mass of Nitrogen in Compound B/(Mass of Nitrogen in Compound C =  0.8750/0.4375 = 2

Mass of Nitrogen in Compound A/(Mass of Nitrogen in Compound C =  1.750/0.4375= 4

Mass of Nitrogen in Compound A/(Mass of Nitrogen in Compound B =  1.750/0.8750= 2

Given that the masses of Nitrogen in the three compounds are in small whole number ratios, the three compounds, Compound A, Compound B, and Compound C are different compounds.

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Answer:

A) 14. 25 × 10²³ Carbon atoms

B) 34.72 grams

Explanation:

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If 8 atoms of Hydrogrn are present in 1 molecule of propane.

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\mathfrak{ \frac{3.8 }{8} \times 10 ^{24}}

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No. of Carbon atoms in 1 molecule of propane = 3

=> C atoms in 4.75× 10²³ molecules of Propane = 3 × 4.75 × 10²³

<u>= 14.25 × 10²³ </u>

<u>________________________________________</u>

<u>Gram</u><u> </u><u>Molecular</u><u> </u><u>Mass</u><u> </u><u>of</u><u> </u><u>Propane</u><u>(</u><u>C3H8</u><u>)</u>

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\mathsf{ \frac{44 }{6.02 \times  {10}^{23} } \times 4.75 \times  {10}^{23}  }

\mathsf{  = \frac{44 }{6.02 \times   \cancel{{10}^{23} }} \times 4.75 \times \cancel{ {10}^{23}}  }

\mathsf{  = \frac{44 }{6.02 } \times 4.75   }

<u>= 34.72 g</u>

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