Draw a mechanism for the reaction of methylamine with propanoic acid. In the box to the left, draw any necessary curved arrows.
Show the products of the reaction in the box to the right. Include any nonzero formal charges and all lone pairs of electrons. Finally, check the box to indicate which side of the reaction is favored at equilibrium.
1 answer:
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Answer:
Option E, Half life =
Explanation:
For a first order reaction, rate constant and half-life is related as:
Where,
= Half life
k = Rate constant
Rate constant given =
So, the correct option is option E.