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3 years ago

What is the pH of a substance that has a hydrogen ion concentration of 8.8x10^(-5) M? *

Chemistry

1 answer:

stealth61 [152]3 years ago

5 0

Answer:

The pH of the substance is 4,06.

Explanation:

The pH indicates the acidity or basicity of a substance. PH values between 0 and less than 7 indicate acidic solutions, 7 neutral and greater than 7 to 14 basic. It is calculated as:

pH = -log (H +)

pH= -log (8.8x10^-5)

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Were is the type of bonds if any (cobalt)

vlada-n [284]

There are three type of bonds.
Ionic bond, Covalent bond, Polar covalent bonds

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2 years ago

Would Nitrogen Dioxide be ionic or covalent

tatiyna

Explanation:

The nitrogen dioxide is a covalent compound where one nitrogen is the central atom which is bonded to two oxygen atoms, where one oxygen atom is bonded by a single bond and other oxygen atom by a double bond.

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2 years ago

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A phase change for carbon dioxide that occurs spontaneously at 20.°C and 1.0 atmosphere is represented by the balanced equation

Troyanec [42]

Answer:

The name of the phase change is;

Sublimation.

Explanation:

CO₂(s) + energy ⇒ CO₂(g)

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As such sublimation is the endothermic process taking place at a temperature and pressure lower than the triple point of the substance in the substance's phase diagram. The triple point is the lowest temperature and pressure at which a substance can exist as a liquid.

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2 years ago

A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound

Karolina [17]

Answer:

The empirical formula of the compound is $C_{0.504}HO_{1.008}$ .

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen ( $H$ ) is scaled up to a mole, since it has the molar mass, and both carbon ( $C$ ) and oxygen ( $O$ ) are also scaled up in the same magnitude. The empirical formula is of the form:

$C_{x}HO_{y}$

Where $x$ , $y$ are the number of moles of the carbon and oxygen, respectively.

The scale factor ( $r$ ), no unit, is calculated by the following formula:

$r = \frac{M_{H}}{m_{H}}$ (1)

Where:

$m_{H}$ - Mass of hydrogen, in grams.

$M_{H}$ - Molar mass of hydrogen, in grams per mole.

If we know that $M_{H} = 1.008\,\frac{g}{mol}$ and $m_{H} = 0.2\,g$ , then the scale factor is:

$r = \frac{1.008}{0.2}$

$r = 5.04$

The molar masses of carbon ( $M_{C}$ ) and oxygen ( $M_{O}$ ) are $12.011\,\frac{g}{mol}$ and $15.999\,\frac{g}{mol}$ , then, the respective numbers of moles are: ( $r = 5.04$ , $m_{C} = 1.2\,g$ , $m_{O} = 3.2\,g$ )