How many grams of KCl are produced when 60 grams of K are reacted?
1 answer:
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<u>Answer:</u> The percent gallium in gallium bromide is 30.30 %.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of gallium bromide = 0.165 g
Molar mass of titanium gallium bromide = 229.53 g/mol
Putting values in equation 1, we get:
- The chemical equation for the reaction of gallium bromide and silver nitrate follows:
By Stoichiometry of the reaction:
1 moles of gallium bromide produces 1 mole of gallium nitrate
So, 0.00072 moles of gallium bromide will produce = of gallium nitrate
- Now, calculating the mass of gallium nitrate from equation 1, we get:
Molar mass of gallium nitrate = 193.73 g/mol
Moles of gallium nitrate = 0.00072 moles
Putting values in equation 1, we get:
Calculating the mass of gallium in the reaction, we use unitary method:
In 1 mole of gallium nitrate, 1 mole of gallium atom is present.
In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.
So, in 0.139 grams of gallium nitrate, the mass of gallium present will be =
- To calculate the percentage composition of gallium in gallium bromide, we use the equation:
Mass of gallium bromide = 0.165 g
Mass of gallium = 0.050 g
Putting values in above equation, we get:
Hence, the percent gallium in gallium bromide is 30.30 %.