Question

The length of the base of a square pyramid is 9 inches the slant height is 12 inches what is the surface area of the pyramid

Answer 1

Answer:

The surface area is $297\ in^{2}$  

Step-by-step explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

$SA=b^{2}+4[\frac{1}{2}(b)(l)]$

where

$b=9\ in$

$l=12\ in$ -----> the slant height

substitute the values

$SA=9^{2}+4[\frac{1}{2}(9)(12)]$

$SA=297\ in^{2}$