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3 years ago

When would maintaining high proteinase inhibitor concentrations in plant tissues be problematic?

1 answer:

7 0

Maintaining high proteinase inhibitor concentrations in plant tissues would be problematic when there would be no herbivores present.

Explanation:

Maintaining high proteinase inhibitor concentrations in plant tissues would be problematic when there would be no herbivores present.
Proteinase inhibitors are found in plants belonging to a variety of systematic groups
Proteinase inhibitors (PI) are there present in the plant tissues, especially in seeds
The food chain would become limited to producers, suppliers and decomposers.
This mite is present in agricultural soils and participatesin the process of organic matter for decomposition.
for the above reason it will be exposed to the PI .

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True or False: One example of a chemical reaction is when H20 (water) melts and changes state from ice to liquid.

Alexus [3.1K]

Answer:

False

Explanation:

Water melting from ice into a liquid is not a chemical reaction or chemical change. It is merely a phase change from solid to liquid.

4 0

3 years ago

Which of the following represents the mass of 1 molecule of SH2?

mr_godi [17]

Answer:
5.645 × 10⁻²³ g

Solution:

Step 1) Calculate Molar Mass of SH₂;

Atomic Mass of Sulfur = 32 g/mol

Atomic Mass of H₂ = 2 g/mol
--------------------
Molecular Mass of SH₂ = 34 g/mol

Step 2: Calculate mass of one molecule of SH₂ as;

As,

Moles = # of Molecules / 6.022 × 10²³

Also, Moles = Mass / M.Mass So,

Mass/M.mass = # of Molecules / 6.022 × 10²³

Solving for Mass,

Mass = # of Molecules × M.mass / 6.022 × 10²³

Putting values,

Mass = (1 Molecule × 34 g.mol⁻¹) ÷ 6.022 × 10²³

Mass = 5.645 × 10⁻²³ g

5 0

4 years ago

Read 2 more answers

A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) <---> N2(g) 3H2(g) At equilibrium, it was fou

Softa [21]

Answer:

Kc for this equilibrium is 2.30*10⁻⁶

Explanation:

Equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction and the concentrations of reactants and products are held constant.

Being:

aA + bB ⇔ cC + dD

the equilibrium constant Kc is defined as:

$Kc=\frac{[C]^{c}*[D]^{d} }{[A]^{a} *[B]^{b} }$

In other words, the constant Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients. Kc is constant for a given temperature, that is to say that as the reaction temperature varies, its value varies.

In this case, being:

2 NH₃(g) ⇔ N₂(g) + 3 H₂(g)

the equilibrium constant Kc is:

$Kc=\frac{[N_{2} ]*[H_{2} ]^{3} }{[NH_{3} ]^{2} }$

Being:

[N₂]= 0.0551 M
[H₂]= 0.0183 M
[NH₃]= 0.383 M

and replacing:

$Kc=\frac{0.0551*0.0183^{3} }{0.383^{2} }$

you get:

Kc= 2.30*10⁻⁶

Kc for this equilibrium is 2.30*10⁻⁶

8 0

4 years ago

A fruit drink concentrate is 15% water. how many liters of pure water should be added to 12l of concentrates to produce a mixtur

harkovskaia [24]

1 liter of drink contain water = 15% 12l of drink contain water = 15 % 12l of drink contain water at 15% = 1.8l 12l of drink contain water at 50% = 6l Water to add in 15% water drink = 6l â€“ 1.8l = 4.2l After adding 4.2l of water in 12l 15% water drink, we get 50% water drink.

4 0

4 years ago

Which of these is a mixture of particles that are large enough to scatter or block light

Daniel [21]

The answer is C. because particles settle out over time ,can block light and scatter light .

5 0

3 years ago