Answer:
a) 35°C, the temperature on a hot summer day
b) -11.11°C, the temperature on a cold winter day
c) a 38.88°C fever
d) a furnace operating at 1011.11°C
e) 523.67°F ( theoretically the lowest attainable temperature )
Explanation:
- °C = ( °F - 32 ) / 1.8
- °F = ( 1.8 * °C ) +32
a) 95°F ⇒ °C = ( 95 - 32 ) / 1.8 = 35°C
b) 12°F ⇒ °C = ( 12 - 32 ) / 1.8 = -11.11°C
c) 102°F ⇒ °C = ( 102 -32 ) / 1.8 = 38.88°C
d) 1852°F ⇒ °C = ( 1852 -32 ) / 1.8 = 1011.11°C
e) 273.15°C ⇒ °F = ( 1.8 * 273.15 ) + 32 = 523.67°F
To determine the temperature of the gas, we need to assume ideal gas to use the equation PV=nRT where P represents the pressure, V is the volume, n is the number of moles, T is the temperature and R is the universal gas constant. We calculate as follows:
PV = nRT
T = PV / nR
T = (1.26 atm) ( 208 L ) / 0.08205 L-atm/mol-K ( 9.95 mol )
T = 321.02 K
Hope this answers the question.
<span>The pH is given by the Henderson - Hasselbalch equation:
pH = pKa + log([A-]/[HA])
pH = -log(</span><span>1.3 x 10^-5) + log(0.50/0.40)
pH = 4.98
The answer to this question is 4.98.
</span>
Answer:
0.500 mole of Xe (g) occupies 11.2 L at STP.
General Formulas and Concepts:
<u>Gas Laws</u>
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Stoichiometry</u>
- Mole ratio
- Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
<em>Identify.</em>
0.500 mole Xe (g)
<u>Step 2: Convert</u>
- [DA] Set up:
- [DA] Evaluate:
Topic: AP Chemistry
Unit: Stoichiometry
