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Pachacha [2.7K]
3 years ago
13

What is the name of the compound below?

Chemistry
1 answer:
stellarik [79]3 years ago
6 0

Explanation:

Butyl propanoate

........

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What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chem
Ainat [17]

Answer:  0.002 M

Explanation:

The balanced chemical equation for ionization of H_2SO_4 in water is:

H_2SO_4\rightarrow 2H^++SO_4^{2-}

According to stoichiometry :

1 mole of H_2SO_4 ionizes to give =2 mole of H^+ ions

0.001 mole of H_2SO_4 ionizes to give = \frac{2}{1}\times 0.001=0.002 mole of H^+ ions

Thus H^+ of a solution of 0.001 M aqueous sulfuric acid is 0.002 M

4 0
3 years ago
What is the molar mass of C4H10
Phantasy [73]
Your answer would be 58.12g/mol ;)
7 0
4 years ago
Predict the geometry about each interior atom in acetic acid:
aleksandr82 [10.1K]

The atomic structure of the acetic acid is:

                        H     O

                        l       l

                H – C – C – O – H

                        l

                        H

 

We can see from the structure that there are 2 interior atoms, and these are all Carbon atoms.


The geometry is:

Tetrahedral on First Carbon

Trigonal Planar on Second Carbon

5 0
3 years ago
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
Salsk061 [2.6K]

Answer:

kp= 3.1 x 10^(-2)

Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

                                2SO2      +        O2         ⇄              2SO3

Initial                      3.4 atm           1.3 atm                         0 atm

Change                    -2x                    - x                                + 2x

Equilibrium            3.4 - 2x            1.3 -x                          0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

                               2SO2             +          O2              ⇄              2SO3

Equilibrium        3.4 - 0.52                1.3 - 0.26                     0.52 atm

Equilibrium        2.88 atm                 1.04 atm                      0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

Kp=\frac{PSO3^2}{PSO2^2 PO2}=\frac{(0.52)^2}{(2.88)^2(1.04)}=0.03135

8 0
3 years ago
*What type of circuit is this in the picture?
galben [10]

Answer:

B: parallel

Explanation:

because a parallel circuit has two or more paths for current to flow through. Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source.

8 0
3 years ago
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