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emmasim [6.3K]
3 years ago
8

Please I really lost on this need need help

Physics
1 answer:
Tpy6a [65]3 years ago
3 0
Kinetic energy being transformed into thermal may be rubbing your hands together, don’t quote me on that though. I hated physics.
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Hydrogen compounds in the solar system can condense into ices only beyond the __________.
Aleonysh [2.5K]

Answer:

frost line.

Explanation:

3 0
3 years ago
Some hydrogen gas is enclosed within a chamber being held at 200^\ { C} with a volume of 0.025 \rm m^3. The chamber is fitted wi
vlada-n [284]

Answer:

The final volume is 0.039 m^3

Explanation:

<u>Data:</u>

Initial temperature: T1=200C

Final temperature: T2=200C

Initial pressure: P1=1.50 \times10^6 Pa

Final pressure: P2=0.950 \times10^6 Pa

Initial volume: V1=0.025m^{3}

Final volume: V2=?

Assuming hydrogen gas as a perfect gas it satisfies the perfect gas equation:

\frac{PV}{T}=nR (1)

With P the pressure, V the volume, T the temperature, R the perfect gas constant and n the number of moles. If no gas escapes the number of moles of the gas remain constant so the right side of equation (1) is a constant, that allows to equate:

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

Subscript 2 referring to final state and 1 to initial state.

solving for V2:

V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}=\frac{(1.50 \times10^6)(0.025)(200)}{(200)(0.950 \times10^6)}

V_{2}=0.039 m^3

3 0
4 years ago
What is the Kinetic Energy of a pie with a mass of 5 kg travelling at a velocity of 9m/s towards your face ?
Stolb23 [73]

Answer:

K = 202.5 J

Explanation:

Given that,

Mass of pie is 5 kg

Velocity of pie is 9 m/s

We need to find the kinetic energy of a pie. The kinetic energy of an object is due to its motion. It can be given by the formula as follows :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 5\times (9)^2\\\\K=202.5\ J

So, the kinetic energy of the pie is 202.5 J.

4 0
3 years ago
Two male moose charge at each other with the same speed and meet on a icy patch of tundra. As they collide, their antlers lock t
Ksenya-84 [330]
Change in velocity of larger moose: (1/3)v - v = -(2/3)v 
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.



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4 0
4 years ago
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