Question

Assuming this rate to be constant how many years will pass before the radius of the Moon's orbit increases by 3.6 x 10^6 m

Answer 1

The number of years that will pass before the radius of the Moon's orbit increases by 3.6 x 10^6 m will be 90000000 years.

How to compute the value?

From the information given, the orbit of the moon is increasing in radius at approximately 4.0cm/yr.

Therefore, we will convey the centimeters to meter. This will be 4cm will be:

= 4/100 = 0.04m/yr.

Time = Distance / Speed

Time = 3.6 x 10^6/0.04

Time = 90000000 years.

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Complete question:

Tidal friction is slowing the rotation of the Earth. As a result, the orbit of the moon is increasing in radius at approximately 4.0cm/y. Assuming this rate to be constant how many years will pass before the radius of the Moon's orbit increases by 3.6 x 10^6